A pattern of growth<span> in which, in a new environment, the </span>population<span> density of an organism increases slowly initially, in a positive acceleration phase; then increases rapidly, approaching an exponential </span>growth<span> rate</span>
Answer:
1. Five classes in the frequency distribution
2.The mid point of the third class is 24.5
3.The total number of frequency is 100
4.The relative frequency of the third class is (20/100=0.2)
5. We use n-1 because we are dealing with a sample data
6. The mean is 24.5
7. The value of the standard deviation is 11
Step-by-step explanation:
See attached picture for the solutions
Answer:
0.006410256
Step-by-step explanation:
Answer:
NM > LN
Step-by-step explanation:
Here, we want to write an inequality
we should beat it in mind that, the greater the angle that a side of a triangle faces, the greater its length will be relatively
as we can see, the side NM faces the greater angle of 83, relative to the side LN that faces the angle of 56;
So we can conclude that;
NM > LN
The formula we use for continuous compounding is

where P is the initial amount invested, r is the rate as a decimal, and t is time in years. Our P = 1300, our r = .042, and our t = 5.75 (9 months is 3/4 of a year, and 3/4 in a decimal is .75). Putting all that into our formula we have

. We have to multiply those 2 powers together and then raise euler's number to it, then multiply by 1300. Doing all of that, we get the amount at the end to be $1,655.10