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Margarita [4]
3 years ago
8

Express in simplest radical form. V112 Answer: Submit Answer

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
4 0
It would be 4 √7 that’s what i got
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One more dilation problem <br> Write the rule to describe each transformation??
Leto [7]

Answer:

It is stretch.

I hope it helps a little bit.

8 0
2 years ago
Read 2 more answers
3. Solve 2log4y - log4 (5y - 12) = 1/2<br>​
Ilia_Sergeevich [38]

Answer:

y =  4  or y = 6

Step-by-step explanation:

2log4y - log4 (5y - 12) = 1/2

​2log_4(y) - log_4(5y-12) = log_4(2)           apply law of logarithms

log_4(y^2) + log_4(1/(5y-12)) = log_4(/2)    apply law of logarithms

log_4(y^2/(5y-12)) = log_4(2)                     remove logarithm

y^2/(5y-12) = 2                                            cross multiply

y^2 = 10y-24                                                  rearrange and factor

y^2 - 10y + 24 = 0

(y-4)(y-6) = 0

y= 4 or y=6

4 0
3 years ago
1. Ella has 7 rolls and 6 loose medium shirts. Each shirt costs $10. What is the value of her
weqwewe [10]

Answer:

the value of her medium shirts is $60 if Ella makes 100 more shirts her new value is $600

6 0
2 years ago
Use the power series for 1 1−x to find a power series representation of f(x) = ln(1−x). What is the radius of convergence? (Note
Viktor [21]

a. Recall that

\displaystyle\int\frac{\mathrm dx}{1-x}=-\ln|1-x|+C

For |x|, we have

\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n

By integrating both sides, we get

\displaystyle-\ln(1-x)=C+\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}

If x=0, then

\displaystyle-\ln1=C+\sum_{n=0}^\infty\frac{0^{n+1}}{n+1}\implies 0=C+0\implies C=0

so that

\displaystyle\ln(1-x)=-\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}

We can shift the index to simplify the sum slightly.

\displaystyle\ln(1-x)=-\sum_{n=1}^\infty\frac{x^n}n

b. The power series for x\ln(1-x) can be obtained simply by multiplying both sides of the series above by x.

\displaystyle x\ln(1-x)=-\sum_{n=1}^\infty\frac{x^{n+1}}n

c. We have

\ln2=-\dfrac\ln12=-\ln\left(1-\dfrac12\right)

\displaystyle\implies\ln2=\sum_{n=1}^\infty\frac1{n2^n}

4 0
3 years ago
Luke has $21 more than Rachel and $48 more than Daniel. All together they have $
KengaRu [80]
This can be solve by 3 variable equation
let x be the money of luke
y money of rachel
z money of daniel
first equation
x = y + 21
second equation
x = z + 48
third equation
x + y + z = 168
solving simultaneously
x =79
y = 58
z = 31

3 0
3 years ago
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