AC is a tangent so by definition, it touches the circle at exactly one point (point C) and forms a right angle at the tangency point. So angle ACO is 90 degrees
The remaining angle OAC must be 45 degrees because we need to have all three angles add to 180
45+45+90 = 90+90 = 180
Alternatively you can solve algebraically like so
(angle OAC) + (angle OCA) + (angle COA) = 180
(angle OAC) + (90 degrees) + (45 degrees) = 180
(angle OAC) + 90+45 = 180
(angle OAC) + 135 = 180
(angle OAC) + 135 - 135 = 180 - 135
angle OAC = 45 degrees
Side Note: Triangle OCA is an isosceles right triangle. It is of the template 45-45-90.
Answer:
k = -7
Step-by-step explanation:
Solve for k:
-7 k - 44 = k + 12
Subtract k from both sides:
(-7 k - k) - 44 = (k - k) + 12
-7 k - k = -8 k:
-8 k - 44 = (k - k) + 12
k - k = 0:
-8 k - 44 = 12
Add 44 to both sides:
(44 - 44) - 8 k = 44 + 12
44 - 44 = 0:
-8 k = 12 + 44
12 + 44 = 56:
-8 k = 56
Divide both sides of -8 k = 56 by -8:
(-8 k)/(-8) = 56/(-8)
(-8)/(-8) = 1:
k = 56/(-8)
The gcd of 56 and -8 is 8, so 56/(-8) = (8×7)/(8 (-1)) = 8/8×7/(-1) = 7/(-1):
k = 7/(-1)
Multiply numerator and denominator of 7/(-1) by -1:
Answer: k = -7
Step-by-step explanation:
Keep quit when they a teaching you and stay with participanting people/friends
Answer:
i dont see a question .
Step-by-step explanation:
