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3 years ago

X=?? solve for x hurry!

Mathematics

1 answer:

jarptica [38.1K]3 years ago

7 0

Answer: x + 30 + 90= 180(sum of angles on a straight line)

x= 180-120

x=60

You might be interested in

How do I solve for d if d/M-3=R

nignag [31]

Answer:

d = (R+3)(M)

Step-by-step explanation:

d/M - 3 = R

Add 3 both sides

d/M = R+3

Multiply M both sides

d = (R+3)(M)

Hope this helps!

5 0

3 years ago

Help pls! Brainliest!

blagie [28]

Answer:

y =-3000x +12000

Step-by-step explanation:

answer is

1) 12000 is the constant therefore when the number of hours is 0 the tickets are 12000

2) the number of tickets (y) are reducing by 3000 for each hour(x). thus the coefficient of variable x should be -3000 (negative because it is reducing)

8 0

3 years ago

What is the cost of six filters if the cost of 8 filterscost$39.92

Usimov [2.4K]

With this given information that 8 filters = $39.92. What you can do is divide $39.92 by 8 and get the individual price of 1 filter. So, $39.92/8 = $4.99 (price of 1 filter). The question is asking for the cost of 6 filters so you can multiply $4.99 with 6 filters and get $29.94. The answer is $29.94 for 6 filters.

8 0

3 years ago

2[3(4^2 +1)] - 2^3.

Rina8888 [55]

Answer:

Step-by-step explanation

P.E.M.D.A.S

4^2=16

(16+1)=17

[3(17)]=51

2[51]=102

2^3=8

102-8=94

5 0

3 years ago

A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th

Valentin [98]

Answer:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=12.8$

The sample deviation calculated $s=4.324 \approx 4.3$

$12.8-4.604\frac{4.324}{\sqrt{5}}=3.896$

$12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704$

So on this case the 99% confidence interval would be given by (3.896;21.704)

Step-by-step explanation:

Data: 10,9,20,13,12

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=12.8$

The sample deviation calculated $s=4.324$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,4)".And we see that $t_{\alpha/2}=4.604$

Now we have everything in order to replace into formula (1):

$12.8-4.604\frac{4.324}{\sqrt{5}}=3.896$

$12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704$

So on this case the 99% confidence interval would be given by (3.896;21.704)

6 0

3 years ago