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liq [111]
2 years ago
8

Andrew has 40/100 of dollars. What are two possible combinations of coins that he could have?

Mathematics
2 answers:
ivolga24 [154]2 years ago
6 0

Hey there!

He can get 5 pennies, 3 dimes, and 1 nickel. Or, he can get 10 pennies, 2 dimes, and 2 nickels.

Hope this helps! Have a great day!

Slav-nsk [51]2 years ago
4 0

Answer:

1- 40 pennies

2- 4 dimes

Step-by-step explanation:

one penny is one cent => 40 pennies is 40 cents

one dime is 10 cents => 4 dimes is 40 cents

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What is the area of the parallelogram?
Bezzdna [24]

The area of the parallelogram is mathematically given as

A = 7 square units Option B

<h3>What is the area of the parallelogram?</h3>

Generally, the equation for a parallelogram is mathematically given as

A=bH

Where

b=\sqrt{4^2+1^2}

b=4.123

and

H=1.75

Hence

A=3*1.75

A=7.2square units

In conclusion,  a parallelogram

A = 7 square units

Read more about parallelogram

brainly.com/question/1563728

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6 0
1 year ago
HELP PLEASE whats the rate of change
poizon [28]
ROC is often used when speaking about momentum, and it can generally be expressed as a ratio between a change in one variable relative to a corresponding change in another; graphically, the rate of change is represented by the slope of a line.
6 0
3 years ago
PLEASE HELP URGENT ILL GIVE 25 POINT.
Rama09 [41]

Answer:

C

Step-by-step explanation:

I think that this is talking about which sides match up with each other and if that is the case the answer would be C

7 0
2 years ago
(01.02 MC)which value is equivalent to 8x4x2
posledela

Answer:

64

Step-by-step explanation:

Multiplication

8 * 4 = 32

32* 2 = 64

3 0
3 years ago
Let <img src="https://tex.z-dn.net/?f=f%28x%2Cy%29%20%3D%20%5Cfrac%7Bx%5E%7B2%7D%20y%7D%7Bx%5E%7B4%7D%2By%5E%7B2%7D%20%7D" id="T
stiv31 [10]

The correct answer is C.

The limit in A does exist:

\displaystyle \lim_{x\to0} f(x,0) = \lim_{x\to0} \frac0{x^4} = 0

The limit in B also exists: for any k\in\Bbb R,

\displaystyle \lim_{x\to0} f(x,kx) = \lim_{x\to0} \frac{kx^3}{x^4+k^2x^2} = \lim_{x\to0}\frac{kx}{x^2+k^2} = 0

But this alone does not prove the 2D limit exists. y=kx only captures all the paths through the origin that are straight lines.

The limit in C also exists, but it's not the same as either of the limits along the paths used in A and B.

\displaystyle \lim_{x\to0} f(x,x^2) = \lim_{x\to0} \frac{x^4}{2x^4} = \frac12

That this value is non-zero tells us the original limit does not exist.

The claim in D is generally not correct. That f(0,0) is undefined does not automatically mean the limit doesn't exist. A simpler example:

\displaystyle \lim_{x\to0} \frac{x}{x} = \lim_{x\to0} 1 = 1

yet \frac00 is undefined.

3 0
1 year ago
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