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2 years ago

Given the quadratic equation X2 - 5x + 10 = 0

Mathematics

1 answer:

lbvjy [14]2 years ago

7 0

Answer:

Step-by-step explanation:

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Please help i will mark branliest

konstantin123 [22]

Answer:

Step-by-step explanation:

The range is the difference between the largest and smallest values.

range = 9 - 2 = 7

If 2 is replaced by 3 then 3 becomes the smallest value and

range = 9 - 3 = 6

That is the range decreases by 1

7 0

3 years ago

A triangle with side lengths of 3, 4, and 5 forms a right triangle. True False

Artyom0805 [142]

True It forms a 30, 60, 90 triangle and 3, 4, and 5 are what we call a Pythagorean Triple, If you don't know what that is, ask your teacher, I'm sure they will either get to it later or will tell you right then and there! :)

5 0

3 years ago

Read 2 more answers

Find the value of x.

stepladder [879]

a straight line is 180 degrees

so on one side of A you have 98 so 180 - 98 = 82

82 + 32 = 114

180-114 = x = 66 degrees

5 0

3 years ago

(X^2+y^2+x)dx+xydy=0 Solve for general solution

aksik [14]

Check if the equation is exact, which happens for ODEs of the form

$M(x,y)\,\mathrm dx+N(x,y)\,\mathrm dy=0$

if $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ .

We have

$M(x,y)=x^2+y^2+x\implies\dfrac{\partial M}{\partial y}=2y$

$N(x,y)=xy\implies\dfrac{\partial N}{\partial x}=y$

so the ODE is not quite exact, but we can find an integrating factor $\mu(x,y)$ so that

$\mu(x,y)M(x,y)\,\mathrm dx+\mu(x,y)N(x,y)\,\mathrm dy=0$

is exact, which would require

$\dfrac{\partial(\mu M)}{\partial y}=\dfrac{\partial(\mu N)}{\partial x}\implies \dfrac{\partial\mu}{\partial y}M+\mu\dfrac{\partial M}{\partial y}=\dfrac{\partial\mu}{\partial x}N+\mu\dfrac{\partial N}{\partial x}$

$\implies\mu\left(\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}\right)=M\dfrac{\partial\mu}{\partial y}-N\dfrac{\partial\mu}{\partial x}$

Notice that

$\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}=y-2y=-y$

is independent of x, and dividing this by $N(x,y)=xy$ gives an expression independent of y. If we assume $\mu=\mu(x)$ is a function of x alone, then $\frac{\partial\mu}{\partial y}=0$ , and the partial differential equation above gives