Answer:
Credit to Prepaid insurance for $400 and Debit to Insurance expense for $400
Explanation:
The journal entry is given below:
Insurance expense ($4800 × 1 ÷ 12) $400
Prepaid Insurance $400
(To record insurance expense)
Here the insurance expense is debited as it increased the expense and credited the prepaid insurance as it decreased the assets
Answer:
$2,800
Explanation:
Particulars Amount
Favorable temporary difference at the end of 20X2 $7000
* Income tax rate <u> 40% </u>
Deferred tax asset account at the end of 20X2 <u>$2,800</u>
Answer:
The correct answer is letter "D": when the actual price is less than the standard price.
Explanation:
Direct labor rate variance compares the existing direct labor costs and normal direct labor costs over the same operating period. Favorable variance in the labor rate can be caused by hiring more unskilled employees, reducing the minimum wage, and incorrectly setting indirect labor costs. Favorable variance takes place when the <em>costs of direct labor are efficient or lower compared to the standard</em>.
Answer:
a differentiation advantage
Explanation:
This scenario best illustrates a differentiation advantage. This is basically when a company is able to offer a product that, despite being the same as the competitor's product, is slightly different or offers something that the competitors do not. This small difference is what attracts the customers and increases profits. In this case, Fashion Mart Corp is differentiating their product by providing a guarantee of quality, which the competitors offering similar products cannot offer.
Answer:
Option (d) , Bank 4 offers the highest amount after a year
Explanation:
The total amount from each of the interest rates can be expressed as;
A=P(1+r/n)^nt
where;
A=Future value of investment
P=Initial value of investment
r=Annual interest rate
n=Number of times the interest is compounded annually
t=number of years of the investment
a). Bank 1
P=x
r=6.1%=6.1/100=0.061
n=1
t=assume number of years=1
replacing;
A=x(1+0.061/1)^(1×1)
A=x(1.061)
A=1.061 x
b). Bank 2
P=x
r=6%=6/100=0.06
n=12
t=1
Replacing;
A=x(1+0.06/12)^(12×1)
A=x(1.005)^12
A=1.0617 x
c). Bank 3
P=x
r=6%=6/100=0.06
n=1
t=1
Replacing;
A=x(1+0.06/1)^(1)
A=1.0600 x
d). Bank 4
P=x
r=6%=6/100=0.06
n=4
t=1
A=x(1+0.06/4)^(4×1)
A=x(1+0.015)^4
A=x(1.061)
A=1.0614 x
e). Bank 5
P=x
r=6%=6/100=0.06
n=365
t=1
A=x(1+0.06/365)^(365×1)
A=1.0618
Option (d) , Bank 4 offers the highest amount after a year