Answer:
1.
centre(h,k)=(-13,9)
radius (r)=6
we have
equation of the circle is
(x-h)²+(y-k)²=r²
(x+13)²+(y-9)²=6²
x²+26x+169+y²-18y+81=36
x²+y²+26x-18y+169+81-36=0
x²+y²+26x-18y +214=0
is a required equation of the circle.
2.
centre(h,k)=(1,-1)
radius (r)=11
we have
equation of the circle is
(x-h)²+(y-k)²=r²
(x-1)²+(y+1)²=11²
x²-2x+1+y²+2y+1=121
x²+y²-2x+2y=121-2
x²+y²-2x+2y=119
is a required equation of the circle.
Find where the equation is undefined ( when the denominator is equal to 0.
Since they say x = 5, replace x in the equation see which ones equal o:
5-5 = 0
So we know the denominator has to be (x-5), this now narrows it down to the first two answers.
To find the horizontal asymptote, we need to look at an equation for a rational function: R(x) = ax^n / bx^m, where n is the degree of the numerator and m is the degree of the denominator.
In the equations given neither the numerator or denominators have an exponent ( neither are raised to a power)
so the degrees would be equal.
Since they are equal the horizontal asymptote is the y-intercept, which is given as -2.
This makes the first choice the correct answer.
Answer:
I think 200x3
Step-by-step explanation:
200x3 = 600
Answer:
<h2>C.</h2>
Step-by-step explanation:
<, > - open circle
≤, ≥ - solid circle
<, ≤ - draw to the left
>, ≥ - draw to the right
