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umka21 [38]
2 years ago
7

PLEASE HELP ME I'M DESPERATE. Delta Math Question!!!

Mathematics
1 answer:
makkiz [27]2 years ago
7 0

Answer:

cos S = \frac{7}{25}

Step-by-step explanation:

this is a 7- 24- 25 right angle with RS = 7 , then

cos S = \frac{adjacent}{hypotenuse} = \frac{RS}{QS} = \frac{7}{25}

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That’s answer is A)-3,4) because you reflect as follows
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Please Help!!<br><br>Use Euler’s formula to write in exponential form.
LekaFEV [45]

Answer:

C, 4e^{i(7\pi/4)}

Step-by-step explanation:

To remind you, Euler's formula gives a link between trigonometric and exponential functions in a very profound way:

e^{ix}=\cos{x}+i\sin{x}

Given the complex number 2\sqrt{2}-2i\sqrt{2}, we want to try to get it in the same form as the right side of Euler's formula. As things are, though, we're unable to, and the reason for that has to do with the fact that both the sine and cosine functions are bound between the values 1 and -1, and 2√2 and -2√2 both lie outside that range.

One thing we could try would be to factor out a 2 to reduce both of those terms, giving us the expression 2(\sqrt{2}-i\sqrt{2})

Still no good. √2 and -√2 are still greater than 1 and less than -1 respectively, so we'll have to reduce them a little more. With some clever thinking, you could factor out another 2, giving us the expression 4\left(\frac{\sqrt{2}}{2} -i\frac{\sqrt{2}}{2}\right) , and <em>now </em>we have something to work with.

Looking back at Euler's formula e^{ix}=\cos{x}+i\sin{x}, we can map our expression inside the parentheses to the one on the right side of the formula, giving us \cos{x}=\frac{\sqrt2}{2} and \sin{x}=-\frac{\sqrt2}{2}, or equivalently:

\cos^{-1}{\frac{\sqrt2}{2} }=\sin^{-1}-\frac{\sqrt2}{2} =x

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4\left(\frac{\sqrt2}{2}-i\frac{\sqrt2}{2}\right)=4e^{i(7\pi/4)}

Which is c on the multiple choice section.

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3 years ago
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The probability that the sample mean is within 2 standard deviations on the high side and 1 standard deviation on the low side is about 0.8186.

5 0
2 years ago
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Tennis balls are sealed in a pressurized container to maintain the rebound percentage
Darina [25.2K]

Answer:

<u>Rounding the results to the next hundredth, we have:</u>

<u>Bounce 1: 2 * 0.55 = 1.10 meters</u>

<u>Bounce 2: 1.10 * 0.55 = 0.61 meters</u>

<u>Bounce 3: 0.61 * 0.55 = 0.34 meters</u>

<u>Bounce 4: 0.34 * 0.55 = 0.19 meters</u>

<u>Bounce 5: 0.19 * 0.55 = 0.10 meters</u>

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Step-by-step explanation:

Rebound percentage = 55% = 0.55

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Bounce 7: 0.05536128 * 0.55 = 0.0304487 meters

<u>Rounding the results to the next hundredth, we have:</u>

<u>Bounce 1: 2 * 0.55 = 1.10 meters</u>

<u>Bounce 2: 1.10 * 0.55 = 0.61 meters</u>

<u>Bounce 3: 0.61 * 0.55 = 0.34 meters</u>

<u>Bounce 4: 0.34 * 0.55 = 0.19 meters</u>

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<u>Bounce 6: 0.10 * 0.55 = 0.06 meters</u>

<u>Bounce 7: 0.06 * 0.55 = 0.03 meters</u>

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Answer:

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3 years ago
Read 2 more answers
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