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Ghella [55]
3 years ago
12

A square pyramid has a base

Mathematics
1 answer:
ozzi3 years ago
4 0

Answer:

V≈25.06m³

Step-by-step explanation:

Unit Conversion:

a≈5.03m

h≈2.97m

Solution

V=a2h 3=5.032·2.97 3≈25.0551m³

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Good job

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A random sample of 16 men have a mean height of 67.5 inches and a standard deviation of 2.22.2 inches. Construct a​ 99% confiden
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Answer: \approx1.49

Step-by-step explanation:

We know that the confidence interval for population standard deviation is given by :-

\sqrt{\dfrac{(n-1)s^2}{\chi^2_{\alpha/2}}}

, where n= sample size

s = sample standard deviation.

\chi^2_{\alpha/2}  and \chi^2_{1-\alpha/2}= Chi-square critical value for degree of freedom (n-1) and significance level (\alpha).

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Critical ch-square values for degree of freedom 15 and \alpha=0.01will be :

\chi_{\alpha/2}=\chi_{0.005}=32.80132

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Then , the required 99% confidence interval for the population standard​ deviation will be :

\sqrt{\dfrac{(15)(2.2)^2}{32.80132}}

\sqrt{2.21332556129}

1.48772496157

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3 years ago
A sanitation department is interested in estimating the mean amount of garbage per bin for all bins in the city. In a random sam
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Answer:

<em>The   95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>

(48.937 , 50.863)

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given data random sample of 46 bins, the sample mean amount was 49.9 pounds and the sample standard deviation was 3.641

<em>The sample size 'n' =46</em>

<em>mean of the sample x⁻ = 49.9</em>

<em>Standard deviation of the sample S = 3.641</em>

<u>Confidence intervals:</u><em>-</em>

<em>The   95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>

<em></em>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha } \frac{S}{\sqrt{n} })<em></em>

<em>Degrees of freedom = n-1  = 46-1 =45</em>

<em>The tabulated value   t₀.₉₆ =   1.794 ( from t-table)</em>

<em></em>(49.9 - 1.794 \frac{3.641}{\sqrt{46} } ,49.9+ 1.794 \frac{3.641}{\sqrt{46} })<em></em>

(49.9 -0.9630 , 49.9+0.9630)

(48.937 , 50.863)

<u>Conclusion:</u>-

<em>The   95.7% confidence interval for the expected amount of garbage per bin for all bins in the city</em>

(48.937 , 50.863)

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