We have two questions, but we need to find the volume of the spherical tank first.
So the formula we will use to find the volume is:
(4/3)πr³=V
Let's fill in the information we have and solve. We will be using 3.14 for pi.
(4/3)(3.14)6³
(4/3)(3.14)(216)
4.1867×216
I'll be using the repeating decimal for 4.1867, I rounded to 7, but there is a repeating 6.
904.32
So the volume is 904.32 yards³ (or 904.78 if using the full pi)
We have to multiply the volume by 7.15.
904.32×7.15
6,465.89
It will cost $6,465.89 to fill the tank with the liquid.
Answer:
6.7
Step-by-step explanation:
For this questions we have the oppsotie side and need the adjacent
out of SOH, CAH, TOA we will sue TOA
tan(56)=10/x
tan(56)/10=1/x
10/tan(56)=x
x=6.745 which rounds to 6.7
Answer:
2 Gallons
Step-by-step explanation:
1 Gallon = 4 quarts
There are 8 quarts, and 8 divided by 4 is 2.
2 Gallons.
LCM=product of highest occurring primes in the numbers prime factorization.
GCF=product of shared primes in the numbers prime factorization.
16=2*2*2*2
Since the GCF is 8 N and 16 share only 2*2*2
Since the LCM is 48 and 16 has 2*2*2*2 the other number has a factor of 3
So the other number is 2*2*2*3=24
N=24
![\bf \cfrac{x}{4x+x^2}\implies \cfrac{\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}{\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(4+x)}\implies \cfrac{1}{4+x}\qquad \{x|x\in \mathbb{R}, x\ne -4\}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7Bx%7D%7B4x%2Bx%5E2%7D%5Cimplies%20%5Ccfrac%7B%5Cbegin%7Bmatrix%7D%20x%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D%7D%7B%5Cbegin%7Bmatrix%7D%20x%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%284%2Bx%29%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B4%2Bx%7D%5Cqquad%20%5C%7Bx%7Cx%5Cin%20%5Cmathbb%7BR%7D%2C%20x%5Cne%20-4%5C%7D)
if you're wondering about the restriction of x ≠ -4, is due to that would make the fraction with a denominator of 0 and thus undefined.
