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3 years ago

“The sum of 6 consecutive integers is 519” what is the third number in this sequence?

1 answer:

7 0

Let x be the first integer, then
:
x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) = 519
:
6x + 15 = 519
:
6x = 504
:
x = 84
:
*****************************
Our sequence is
:
84, 85, 86, 87, 88, 89
:
The third integer is 86

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Answer:

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$(-4)(-9)\\\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a,\:-\left(-a\right)=a\\=4\times\:9\\= 36$

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$(-6)(-6)\\\\\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a,\:-\left(-a\right)=a\\=6\times 6\\\\\mathrm{Multiply\:the\:numbers:}\:6\times\:6\\=36$

$(6)(-6)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=-6\times 6\\\\\mathrm{Multiply\:the\:numbers:}\:6\times \:6=36\\=-36$

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