Question

For what values of k the relation R:{(k2 , 5), (3k, 6)} is not a function?

Answer 1

Answer:

$k=0$ and $k=3$.

Step-by-step explanation:

To this relation be a function, the horizontal coordinates can't be equal. So, let's find the value of $k$ that makes those coordinates equal.

$k^{2}=3k\\ k^{2}-3k=0\\k(k-3)=0$

Using the null factor property, we have

$k=0\\k-3=0 \implies k=3$

Therefore, the given relation is not a function when $k=0$ and $k=3$.