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saw5 [17]
3 years ago
10

For what values of k the relation R:{(k2 , 5), (3k, 6)} is not a function?

Mathematics
1 answer:
Nastasia [14]3 years ago
7 0

Answer:

k=0 and k=3.

Step-by-step explanation:

To this relation be a function, the horizontal coordinates can't be equal. So, let's find the value of k that makes those coordinates equal.

k^{2}=3k\\ k^{2}-3k=0\\k(k-3)=0\\

Using the null factor property, we have

k=0\\k-3=0 \implies k=3

Therefore, the given relation is not a function when k=0 and k=3.

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X to the power of 3 = 125 <br> what is X?
asambeis [7]

Answer:

x = 5

Step-by-step explanation:

x³ = 125

x = √125

x = 5

plz follow me

4 0
3 years ago
PLEASE HELP MEEEEEEEEEEEEE
Harlamova29_29 [7]

Okay, so you have the last option (g(x)=3^x+2-7) as your first line at that is aligned with the x-axis then movies up slightly into Quad. one. Your answer for this is going to be... C. g(x)=3^x-2-7.

You are going to graph these by using only a few selected points, then finding your answer.

Your horizontal Asymptote is y=-7.

x--------------y

-2            -6.988

-1             -6.963

0              -6.889

2              -6

3              -4

Hope this helps you!!!

5 0
4 years ago
If BAC = 320°, what is the measure of BC?
melisa1 [442]

Answer:

BC = 40º

BMC = 40º

Step-by-step explanation: Since the measure the major and minor arcs add up to 360º, just subtract 320 from 360 to find BC which is 40º. <BMC is also 40º because the measure of the arc is equal to its corresponding angle.

3 0
3 years ago
Simplify the equation <br><br> (-0.75x - 3) -(3.5x +8.4 )
sveta [45]
-2.77x - 11.4. Is the answer to your question
8 0
3 years ago
Read 2 more answers
NEED HELP ASAP!!!!
Masja [62]

y=kx

Substitute the given x and y values, and solve for k .

30=k⋅6

k=5

The equation is y=5x . Now substitute x=100 and find y .

y=5⋅100y=500

Sorry If It's Wrong. . .

3 0
3 years ago
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