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Lady_Fox [76]
2 years ago
8

What is x-intercept of y=-3x+5

Mathematics
1 answer:
Yuri [45]2 years ago
6 0

Answer:

To find x intercept, u graph it

the x intercept is 1.67

Step-by-step explanation:

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Rewrite each expression by combining like terms.<br><br> 8pq - 3pq<br><br> 2m - 3m + 4
qaws [65]

Answer:

  1. 8pq-3pq= 5pq
  2. 2m-3m+4 =4-m

Step-by-step explanation:

  1. The first equation shows two terms can be combine as follow: 8pq-3pq= (8-3)pq by applying common factoring. Then, because 8-3=5, it can be expressed as 5pq.
  2. In the second equation, we have only two terms that can be factored by combining the terms that share the same factor (which is m). Then, 2m-3m+4 can be expressed like m(2-3)+4. Because (2-3)=-1 and because the order of the sum does not affect the result, the result is 4-m.
4 0
3 years ago
26 divided by 000.0000000009
Flura [38]

Answer:

undefined

Step-by-step explanation:

The expression contains a division by  

0

The expression is undefined.

Undefined

7 0
3 years ago
Read 2 more answers
Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention
Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

a=\frac{d^2s}{dt^2}

Differentiate the position vector with respect to t.

\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}

Differentiate both sides of the obtained equation with respect to t.

\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}

The initial position is obtained at t=0. Substitute t=0 in the given position function.

\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}

8 0
1 year ago
T=4U/E SOLVE FOR U please please please help please thank you
vlada-n [284]
TE/4 =U
Step by step
You multiply both sides by E to get rid of it then you have TE =4U and then u divide it by 4 and get TE/4 =U
3 0
2 years ago
Someone please help ASAP
kondor19780726 [428]

I haven't done this in a while, but I'm pretty sure the answer is D, (-3, -1.)

If you were to substitute x for -3 and y for -1 in the first inequalities and simplify, it would look like this:

-1 > -3-2

-1 > - 5

And that inequality is true, because -1 is bigger than -5. Let's also substitute in the other inequality, which would be:

-1 > 2(-3) + 2

-1 > -6 + 2

-1 > -4

And -1 is bigger than -4. So, I think the answer would be D because substituting for those values of x and y would stil. make the inequalities true.

5 0
3 years ago
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