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pochemuha
3 years ago
13

Compare the given dimensions of four triangles. Which triangle is possible to construct?

Mathematics
2 answers:
yan [13]3 years ago
7 0
<span>When 3 Triangle sides are known:
</span><span>The longest side must be less than the sum of the other 2 sides.
5, 12 and 13 - can be constructed
</span>2, 11 and 15 <span>- can be constructed
3, 7 and 11 - CAN'T be constructed - the longest side is greater than the sum of the other two.
4, 8 and 15 </span><span>- CAN'T be constructed - the longest side is greater than the sum of the other two
Source:
http://www.1728.org/trianinq.htm

.</span>

mel-nik [20]3 years ago
4 0

Answer:

side lengths of 4 ft, 8 ft, and 15 ft

Step-by-step explanation:

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15 - 2(3 - 2x) = 46<br> Simplify.
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A manufacturer of piston rings for automobile engines frequently tests the width of the rings for quality control. Last week, a
kozerog [31]

Answer:

a) 74.0353 < u <  74.0367

b) 74.036 < u

Step-by-step explanation:

Given:

- Sample size n = 15

- Standard deviation s.d = 0.0001 in

- Sample mean x_bar = 74.036

Find:

A) Calculate the 99% two-sided confidence interval on the true mean piston diameter.

Solution:

- For 99% CI, We have a = 0.01 , and Z_a/2 = 2.58

------> (x_bar - Z_a/2*s.d / sqrt(n)) < u <  (x_bar + Z_a/2*s.d / sqrt(n))

------> (74.036 - 2.58*0.0001 / sqrt(15)) < u <  (74.036 + 2.58*0.0001 / sqrt(15))

------>                               74.0353 < u <  74.0367

Find:

B) Calculate the 95% one-sided lower confidence interval on the true mean piston diameter.

Solution:

- For 95% lower CI, We have a = 0.05 , and Z_a = 1.645

------> (x_bar - Z_a/2*s.d / sqrt(n)) < u

------> (74.036 - 1.645*0.0001 / sqrt(15)) < u

------>                               74.036 < u

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Step-by-step explanation:

=0.25x-12 I hope this helped:)

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36b - 9 = 2b + 6 \\ 34b = 15 \\ b =  \frac{15}{34}
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3 years ago
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