We have a segment, for which we know one endpoint T=(2,4) and the midpoint M=(3, 6.5).
We have to find the other endpoint, lets call it S.
Both for the x-coordinates and y-coordinates the distance in each axis from T to M (TM) has to be equal to the distance M to S (MS).
Then, if we look at the x-axis, we have that the distance is TMx=2-3=-1.
Then, S has to be one unit above M: the x-coordinate of S is xS=4.
We do the same for the y-axis. The distance TMy is TMy=4-6.5=-2.5.
Then, S has to be 2.5 units above M: the y-coordinate of S is yS=(6.5+2.5)=9.
The coordinates of S are (4,9).
Graph:
2, 11, 31, 59 and 97 are all prime numbers.
The simplest form for 0.41 is 41/100. 41 and 100 do not have common factors so they cannot be simplified.
First let's review how to expand this!
(ax+b)^2=a^2*x^2+2abx+a^2
In this case
(2x^2+1/2)^2=2^2*x^2+2*1/2*2x+(1/2)^2
=4x^2+2x+1/4
Done!