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Sveta_85 [38]
2 years ago
15

Un campo de fútbol mide de largo 105m y de ancho 65m¿cuál es el área total del campo de fútbol?​

Mathematics
1 answer:
Jet001 [13]2 years ago
7 0

Answer:

6825

Step-by-step explanation:

area=largo X ancho

area= 105 x  65=  6825

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9x+3y=18 whats is the equation when solved for y
lidiya [134]

Answer:

y=6-3x

Step-by-step explanation:

first subtract 9x from 9x+3y=18

                                   -9x       -9x

so you get 3y=18-9x or 3y=-9x+18 then divide both sides by 3

so you get y=6-3x hope this helps :)

6 0
2 years ago
The lifetime of LCD TV sets follows an exponential distribution with a mean of 100,000 hours. Compute the probability a televisi
kondaur [170]

Answer:

0.9

0.3012

0.1809

230258.5

Step-by-step explanation:

Given that:

μ = 100,000

λ = 1/μ = 1 / 100000 = 0.00001

a. Fails in less than 10,000 hours.

P(X < 10,000) = 1 - e^-λx

x = 10,000

P(X < 10,000) = 1 - e^-(0.00001 * 10000)

= 1 - e^-0.1

= 1 - 0.1

= 0.9

b. Lasts more than 120,000 hours.

X more than 120000

P(X > 120,000) = e^-λx

P(X > 120,000) = e^-(0.00001 * 120000)

P(X > 120,000) = e^-1.2

= 0.3011942 = 0.3012

c. Fails between 60,000 and 100,000 hours of use.

P(X < 60000) = 1 - e^-λx

x = 60000

P(X < 60,000) = 1 - e^-(0.00001 * 60000)

= 1 - e-^-0.6

= 1 - 0.5488116

= 0.4511883

P(X < 100000) = 1 - e^-λx

x = 100000

P(X < 60,000) = 1 - e^-(0.00001 * 100000)

= 1 - e^-1

= 1 - 0.3678794

= 0.6321205

Hence,

0.6321205 - 0.4511883 = 0.1809322

d. Find the 90th percentile. So 10 percent of the TV sets last more than what length of time?

P(x > x) = 10% = 0.1

P(x > x) = e^-λx

0.1 = e^-0.00001 * x

Take the In

−2.302585 = - 0.00001x

2.302585 / 0.00001

= 230258.5

3 0
3 years ago
Can some help me to find the surface area of the figure step by step
elena-s [515]
Try out this website or search "surface area of a triangular prism" in Google
http://www.ck12.org/geometry/Surface-Area-of-Triangular-Prisms/lesson/Surface-Area-of-Triangular-Pri...
4 0
3 years ago
27. The average hourly wage of workers at a fast food restaurant is $7.25/hr
morpeh [17]

Answer:

0.0668 = 6.68% probability that the worker earns more than $8.00

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The average hourly wage of workers at a fast food restaurant is $7.25/hr with a standard deviation of $0.50.

This means that \mu = 7.25, \sigma = 0.5

If a worker at this fast food restaurant is selected at random, what is the probability that the worker earns more than $8.00?

This is 1 subtracted by the pvalue of Z when X = 8. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8 - 7.25}{0.5}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 = 6.68% probability that the worker earns more than $8.00

8 0
3 years ago
Dillion divided a 3 1/3 pound bag of pears among his 5 friends. How many pounds of pears does did each friend revive?
IgorLugansk [536]

Your answer is .6 repeating or 2/3 per person.

8 0
3 years ago
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