Answer:
Those graphs do not intersect.
Estes gráficos no se intersecciónan
Step-by-step explanation:
The intersection points are x for which:

In this question:


So


Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots
such that
, given by the following formulas:



In this question:

So 

Sincce
is negative, there are no solutions, which means that those graphs do not intersect.
You didn't include the formula.
Given that there is no data about the mass, I will suppose that the formula is that of the simple pendulum (which is only valid if the mass is negligible).
Any way my idea is to teach you how to use the formula and you can apply the procedure to the real formula that the problem incorporates.
Simple pendulum formula:
Period = 2π √(L/g)
Square both sides
Period^2 = (2π)^2 L/g
L = [Period / 2π)^2 * g
Period = 3.1 s
2π ≈ 6.28
g ≈ 10 m/s^2
L = [3.1s/6.28]^2 * 10m/s^2 =2.43 m
Hope this helps you!!!!
<span><em>Ps: Please mark brainliest!!!! I am only a few away from ranking up, it would help a lot, and I will make a shoutout for you!! </em></span>
oksn ethe ansetware its 738wuy79q246978t59723482709uy783271-047892=-39074-2378904-2139047=123473192709270329742109372301790
Step-by-step explanation:
Answer:
Density = 10,490 g/m³
Step-by-step explanation:
Density = mass ÷ volume
here mass = 73,430 g
volume = 7 m³
density = 73,430 ÷ 7
= 10490 g/m³
Density = 10,490 g/m³
The only thing you should do is to divide $27.60 by 24 so the answer is $1.15 :)))
i hope this is helpful
have a nice day