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ArbitrLikvidat [17]
3 years ago
7

Need help pls ASAP no jokes need this badly

Mathematics
2 answers:
Elanso [62]3 years ago
4 0

Answer:

x=64°

................

Alekssandra [29.7K]3 years ago
3 0
<h3>Answer:  x = 64</h3>

=============================================================

Explanation:

Combining all of the angles shown in the diagram leads to 360 degrees. This is because there are 360 degrees in a full rotation.

Let's add up the angles shown and set the sum equal to 360. Keep in mind that the square angle marker represents 90 degrees (aka a right angle).

180+26+x+90 = 180

x+296 = 360

x = 360-296

x = 64

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A company introduced a much smaller variant of its tablet, known as the tablet junior. Weighing less than 11 ounces, it was abou
Inessa [10]

Answer:

0.2857

Step-by-step explanation:

Given that a company introduced a much smaller variant of its tablet, known as the tablet junior.

The weight was less than 11 oz. i.e. 50% lighter than std.

Let X be the battery life of the tablet junior

Then X is U(8.5,12)

Mean of X =10.25 hrs

the probability that the battery life for a tablet junior will be 9.5 hours or less

=P(X\leq 9.5)\\=F(9.5)\\=\frac{9.5-8.5}{12-8.5} \\=0.2857

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3 years ago
I need the answers to
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Take short showers. Turn water off when brushing teeth. Clean dishes quicker. Fix leaks. Use less water when doing laundry.
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3 years ago
Find the mean of A and find the median on letter B
mash [69]
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3 0
3 years ago
Read 2 more answers
(12a^(2) - 3)/(2)*(2a + 1)^(-2)*((6)/((2a + 1)))^(-1)
Elena L [17]

Answer:

\frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\

Step-by-step explanation:

\frac{(12a^2-3)}{2*(2a+1)^{-2}}*\frac{6}{(2a+1)^{-1} }\\ = \frac{(12a^2-3)}{2 * \frac{1}{(2a+1)^{2} }} * \frac{6}{\frac{1}{2a+1}  }\\ =\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}\\=\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}

= \frac{(12a^2-3)(4a^{2} + 1 + 2 (2a)(1))}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{1} * \frac{3}{2a+1}\\= \frac{3(12a^2-3)(4a^{2} + 1 + 4a)} {2a+1}\\\\= \frac{3(12a^2(4a^{2} + 1 + 4a) - 3 (4a^{2}+1+4a)} {2a+1}\\= \frac{3(48a^{4}+12a^{2}+48a^{3}  - 12a^{2} -12 - 4a)} {2a+1}\\= \frac{144a^{4}+36a^{2}+144a^{3}  - 36a^{2} - 36 - 12a)} {2a+1}

= \frac{144a^{4}+36a^{2}+144a^{3}  - 36a^{2} - 36 - 12a} {2a+1}\\= \frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\

6 0
4 years ago
Find the distance between (8,6) and (4,1). Round the answer to the nearest tenth.
Evgesh-ka [11]
4/3th a 100th per distance of both.
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4 years ago
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