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Vanyuwa [196]
3 years ago
5

Second part need help ASAP

Mathematics
1 answer:
jarptica [38.1K]3 years ago
7 0

statements 13-L , 15-F , 6-G , and 10-C are true statements

hope this helps!

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Please help 10 POINTS!!!
Stella [2.4K]
Y=-1/2x+3



y=-1/2x-5 is parallel:

y=-1/2x-1 is parallel: x+2y=-2

y=2x-4 is perpendicular: -2x+y=-4

y=1/2x+2 is parallel: -x+2y=2
3 0
3 years ago
7th grade math problem! Please help!
ANTONII [103]

Volume of the hexagonal prism = 1732.7772 ft³

Solution:

Height of the prism (H) = 15.4 ft

Side of the hexagon base (b) = 6.58 ft

Height from center to the side length (h) = 5.7 ft.

Let us first find the area of the base.

Area of the base (B) =  6\times\frac{1}{2}\  bh

                                 $=6\times\frac{1}{2}\times 6.58 \times 5.7

Area of the base (B) = 112.518 ft²

To find the volume of the hexagonal prism:

Volume of the hexagonal prism = Area of the base × Height

                                                     = 112.518 × 15.4

                                                     = 1732.7772 ft³

The volume of the hexagonal prism is about 1732.7772 ft³.

3 0
3 years ago
If f(x) = x and g(x) = 2x + 7, what is<br>f[90X)] when g(x) = 11?​
kumpel [21]

\bf \begin{cases} f(x) = x\\ g(x) = 2x+7 \end{cases}~\hspace{7em}g(x)=11\implies \stackrel{g(x)}{11}=2x+7 \\\\\\ 4=2x\implies \cfrac{4}{2}=x\implies \implies \boxed{2=x} \\\\[-0.35em] ~\dotfill\\\\ f[90x]\implies f\left[90\left( \boxed{2} \right)\right]\implies f(180)=\stackrel{x}{180}

8 0
3 years ago
Can a triangle have sides with the given​ lengths? Explain.
Nookie1986 [14]
No because when you add any 2 sides the answer has to be bigger than the 3rd side

ex: 2+7=9
9 is too small, so the tips of the side that is 2ft would not touch the side that is 7ft
4 0
3 years ago
If sec theta = - √30 / 3, find cos theta.<br> if sin(-theta) = -0.97, find cos (π/2 - theta).
Cloud [144]

Step-by-step explanation:

\cos \theta  =  \frac{1}{ \sec\theta }  =  -  \frac{3}{ \sqrt{30} }  =  -  \frac{3 \sqrt{30} }{30}   =  -  \frac{ \sqrt{30} }{10}

\cos( \frac{\pi}{2} -  \theta )=  \cos \frac{\pi}{2}  \cos \theta  +   \sin \frac{\pi}{2}  \sin \theta

Note that

\sin( - \theta) =  -  \sin \theta

\cos \frac{\pi}{2}  = 0 \:  \:  \:  \:  \:  \sin \frac{\pi}{2}  = 1

Therefore,

\cos( \frac{\pi}{2} -  \theta )  = 0.97

5 0
3 years ago
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