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Ymorist [56]
3 years ago
15

Please help 10 POINTS!!!

Mathematics
1 answer:
Stella [2.4K]3 years ago
3 0
Y=-1/2x+3



y=-1/2x-5 is parallel:

y=-1/2x-1 is parallel: x+2y=-2

y=2x-4 is perpendicular: -2x+y=-4

y=1/2x+2 is parallel: -x+2y=2
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2^3+4⋅2−7<br><br> A.1<br> B.5<br> C.9<br> D.36
Rudiy27

The answer is D. I hope I helped

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
When exchanging US Dollars (USD) for Philippine Peso.(PHP) the number of philippine pessos received is directly Proportional to
Tasya [4]

Answer:

1: 36.561

2: 45701.25

Step-by-step explanation:

31076.85/850 = 36.561

36.561*1250=45701.25

3 0
3 years ago
Which is the equation for the line that has a slope of 12 and passes through the point (3, 20)?
Anna007 [38]

Answer:

the first one

Step-by-step explanation:

y-y1=m(x-x1)

y-20=12(x-3)

y-20+20=12\left(x-3\right)+20

simplify:

y=12x-16

4 0
3 years ago
The graph of which of the following equations is a line parallel ot the graph of x-5y=8
kvv77 [185]

Since you don't show the graph, all I can do is to tell you how to identify which function is parallel to the x-5y=8.

First let's rearrange the function.

x-5y=8

5y=x-8

y=1/5x-8/5.

Thus, it gives us the slope of the function, which is 1/5.

And the function that is parallel to the graph would have the SAME slope. Which is 1/5. So all you need to do is to find which function has the SAME SLOPE, in this case: 1/5.

7 0
3 years ago
Evidencia de aprendizaje Se desea obtener 80 kilogramos de café molido mezclando café arábico de S/18 el kilogramo y café torrad
SIZIF [17.4K]

Answer:

50kg de café torrado

30kg de café arábico

Step-by-step explanation:

Queremos obtener un total de 80kg de café molido.

Se utilizarán:

Café arábico, que cuesta $18 el kg

Café torrado, que cuesta $10 el kg

Queremos que el precio, por kilo, de la mezcla de 80kg sea $13.

Ok, primero debemos definir las variables:

Definamos:

x = cantidad de café arábico usado

y = cantidad de café torrado usado.

Entonces, como la mezcla deberá tener 80kg en total, tenemos:

x + y = 80kg

Y el costo total de esta mezcla será:

x*$18 + y*$10

Si lo dividimos por el peso total, tendremos el costo por kilo, que es:

(x*$18 + y*$10)/80kg

Y queremos que esto sea igual a $13, entonces tenemos la ecuación

(x*$18 + y*$10)/80kg = $13

Ok, ahora tenemos dos ecuaciones, es decir, tenemos un sistema de ecuaciones:

x + y = 80kg

(x*$18 + y*$10) = $13*80kg

(donde reescribimos levemente la segunda ecuación)

Ok, para resolver este sistema trataremos de reemplazar variables, para ello, el primer paso es aislar una de las variables en una de las ecuaciones.

Aislemos x en la primera:

x = 80kg - y

Ahora reemplazamos esto en la otra ecuación:

(x*$18 + y*$10) = $13*80kg

(( 80kg - y)*$18 + y*$10) = $13*80kg

Ahora podemos resolver esto para la variable y:

$18*80kg - $18*y + $10*y = $13*80kg

$18*80kg - $13*80kg = $18*y - $10*y

($18 - $13)*80kg = ($18 - $10)*y

$5*80kg = $8*y

($5*80kg)/$8 = y

50kg = y

Se usan 50kg de café torrado.

y como:

x + y = 80kg

x = 80kg - y

x = 80kg - 50kg = 30kg

Entonces los 30kg restantes serán de café arábico.

y la estrategia utilizada fue el remplazo de variables.

6 0
3 years ago
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