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sasho [114]
2 years ago
14

A survey was conducted with a large group of teenagers from 6 different states and it asked them for their favourite sport out o

f a large list of sports. The study aims to look at whether a teenager's state of residence is associated with their sporting preferences. Assume that p is the proportion of teenagers who selected the sport most preferred in their state of residence, such that p1 is that for State 1, p2 is that for State 2 and so on.
Required:
Determine the chi square test association.
Mathematics
1 answer:
UkoKoshka [18]2 years ago
3 0

Answer:

H0: There is no association between state and sporting preference.

H1: There is an association between state and sporting preference

Step-by-step explanation:

The hypothesis to be tested for is whether the factor 'state' is associated with the factor 'sporting preference'.

The study is therefore about 'association' and whether the distributions of sporting preferences are identical across states. In scenario in this case is the test for association which is the most appropriate test.

Two factors are deemed to not be associated unless there is supporting evidence to suggest otherwise. Since the null hypothesis is the default belief, the correct pair of hypotheses are:

H0: There is no association between state and sporting preference.

H1: There is an association between state and sporting preference

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What is the range? (Worth many points)
77julia77 [94]

Answer:

7

Step-by-step explanation:

the range is the difference between the smallest and largest numbers

7 0
3 years ago
Taye recruits two people to be election campaign volunteers. The next week he ask each of those volunteers to recruit two more c
jeka94

Using a geometric sequence, it is found that:

a) For the first 5 weeks, the numbers are: 2, 4, 8, 16, 32

b) Hence some of the volunteers can stop recruiting new volunteers during the 7th week.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

a_n = a_1q^{n-1}

In which a_1 is the first term.

For this problem, on the first week there are 2 people, and since each new people involve two more, the common ratio is of 2, hence the parameters for the geometric sequence are:

a_1 = 2, q = 2

Hence the number of people after n weeks is:

a_n = 2 \times 2^{n - 1}

For the first 5 weeks, the numbers are:

  • a_1 = 2 \times 2^{1 - 1} = 2
  • a_2 = 2 \times 2^{2 - 1} = 4
  • a_3 = 2 \times 2^{3 - 1} = 8
  • a_4 = 2 \times 2^{4 - 1} = 16
  • a_5 = 2 \times 2^{5 - 1} = 32

There will be 150 volunteers when a_n = 150, hence:

2 \times 2^{n - 1} = 150

2^{n-1} = 75

\frac{2^n}{2} = 75

2^n = 150

n = 7...

The above is because 2^7 = 128 and 2^8 = 256, and 128 < 150 < 256.

Hence some of the volunteers can stop recruiting new volunteers during the 7th week.

More can be learned about geometric sequences at brainly.com/question/11847927

#SPJ1

3 0
1 year ago
Alfredo has different colored spiral notebooks in his backpack. Which of the following models could be used to simulate a 1 in 3
BartSMP [9]

Answer:

the fourth option

Step-by-step explanation:

Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.

For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.

Probability of choosing a red spiral = number of red spiral / total sum of spirals in the bag

1st option = 2 / 4 = 1/2

2nd option = 4/8 = 1/2

3rd option = 2/3

4th option = 2/6 = 1/3

the fourth option is correct

4 0
3 years ago
Name collection boxes
kirill115 [55]
How would we do that here
4 0
3 years ago
The sum of two positive integers, x and y, is not more than 40. The difference of the two integers is at least 20. Chaneece choo
Butoxors [25]

Answer:

The value of x lies between 20 and 40 and value of y lies between -20 and 10

Step-by-step explanation:

We are given that

y\leq 40-x....(1)

y\leq x-20...(2)

First we convert inequality equation into equality equation to find the solution of the given system of inequality equation.

Therefore, we can write as

y=-x+40...(3)

y=x-20...(4)

Adding equation (3) and (4) we get

2y=20

y=10

Substitute y=10 in equation (3) we get

10=40-x

x=40-10=30

(30,10) is the intersect point of two equation.

Put x=0 in equation (3)

y=40

Substitute y=0 in equation (3)

x=40

Substitute x=0 in equation (4)

y=-20

Substitute y=0 in equation (4)

x=20

Substitute x=0 and y=40 and in equation (1)

40\leq 40

Hence, the equation is true.Therefore, the shaded region below the line.

Substitute x=0 and y=-20 in equation (2)

-20\leq -20

The equation is true. Hence, the shaded region is below the line.

Hence, the value of x lies between 20 and 40 and value of y lies between -20 and 10.

5 0
3 years ago
Read 2 more answers
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