Answer:
y - 1 = 1/6x + 1 <<< Point slope form
y = 1/6x + 2 <<< slope intercept form
Either one works unless the question specifies the form of the equation
Step-by-step explanation:
Point slope form: (y - y1) = m(x - x1)
Given: (-6,1) ; m = 1/6
(y - 1) = 1/6(x - (-6))
y - 1 = 1/6x + 1 <<< Point slope form
y = 1/6x + 2 <<< slope intercept form: y = mx + b
The derivative is the gradient.
At any local Max's or min's the derivative graph will cut the x axis.
For example a graph x^2
The derivative will have a positive gradient as the gradient is increasing at the lower values then at x=0 the gradient is 0 so the derivative graph will pass the point (0,0). Remember that the derivative graph will be linear.
To get more detail find the points the graph crosses the x axis and put into for a(x-q)(x-p)=0 you will have to solve for 'a' by finding a point on the graph and substituting it in. Then you can find the derivative of that function and graph it
It isn't proportional because it is not reduced to the lowest terms
Instead 20 over 100 = 1 over 5
Hope this helps!
Answer:
a) CI = ( 5,1 ; 5,7 )
b) SE = 0,1
Step-by-step explanation:
a) Sample random n = 100
Mean = μ = 5,4
Standard deviation s = 1,3
CI = 99 % α = 1 % α = 0,01 α/2 = 0,005
z(c) for 0,005 is from z-table z(c) = 2,575
z(c) = ( X - μ ) /s/√n CI = μ ± z(c) * s/√n
CI = 5,4 ± 2,575* 1,3/10
CI = 5,4 ± 0,334
CI = ( 5,1 ; 5,7 )
b) SE = Standard deviation / √n
SE = 1,3 /10 SE = 0,1
We can support that with 99 % of probability our random variable will be in the CI.
