By means of <em>functions</em> theory and the characteristics of <em>linear</em> equations, the <em>absolute</em> extrema of the <em>linear</em> equation f(x) = - 3 · x + 3 are 27 (<em>absolute</em> maximum) for x = - 8 and - 9 (<em>absolute</em> minimum) for x = 4. (- 8, 27) and (4, - 9).
<h3>What are the absolute extrema of a linear equation within a closed interval?</h3>
According to the functions theory, <em>linear</em> equations have no absolute extrema for all <em>real</em> numbers, but things are different for any <em>closed</em> interval as <em>absolute</em> extrema are the ends of <em>linear</em> function. Now we proceed to evaluate the function at each point:
Absolute maximum
f(- 8) = - 3 · (- 8) + 3
f(- 8) = 27
Absolute minimum
f(4) = - 3 · 4 + 3
f(4) = - 9
By means of <em>functions</em> theory and the characteristics of <em>linear</em> equations, the <em>absolute</em> extrema of the <em>linear</em> equation f(x) = - 3 · x + 3 are 27 (<em>absolute</em> maximum) for x = - 8 and - 9 (<em>absolute</em> minimum) for x = 4. (- 8, 27) and (4, - 9).
To learn more on absolute extrema: brainly.com/question/2272467
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Answer:
G=m/r-h^2
Step-by-step explanation:
move all the terms to the left side and set equal to zero. Then set each factor equal to zero. Hope this helps!
Answer:
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Step-by-step explanation:
They want you to find the y intercept. This is the point where the curve or line crosses the y axis. To find the y intercept, plug in x = 0
y = 3x+4
y = 3*x + 4
y = 3*0 + 4 ... notice x has been replaced with 0
y = 0 + 4
y = 4
So when x = 0, the value of y is y = 4. This means the y intercept is located at the point (0,4). This is all for problem 1. Problem 2 is handled much the same way.
