⇒ common ratio =r=3 and the given sequence is geometric sequence. Where an is the nth term, a is the first term and n is the number of terms. ⇒ 12th term is 708588 .
(May be wrong for some other users, although it's correct for me.)
Answer:
a. 2.6(0.12)
Step-by-step explanation:
Check all of the other answers: b. c. and d. are variations of equations that equal to 2.912. 2.6(0.12) is not the correct equation because it equals to 0.312. The kitten‘s weight must increase, so that is the incorrect equation.
Think about it for a minute and take a deep breath. you’ll be ok. i’m solving it rn please give me a minute
Answer:
the average rate of change rc is 13 , 12.1 and 12.01 for h=1 , 0.1 and 0.01 respectively
Step-by-step explanation:
for
R(t) = 30*t − 3*t² ; t = 3
the average rate of change of R(t) over the time interval [t, t + h] is
rc= [R(t+h)-R(t)] / [(t+h) -t) = [R(t+h)-R(t)] /h = 1/h * [ 30*(t+h) − 3*(t+h)² - ( 30*t − 3*t² ) ] = (1/h) * ( 30*h - (3*t² + 6*t*h + t²) +3*t² ) = 30 - 6*t + h
then
rc= 30 - 6*t + h
for t=3 and h=1
rc= 30 - 6*3 + 1 = 13
for t=3 and h=0.1
rc= 30 - 6*3 + 0.1 = 12.1
for t=3 and h=0.01
rc= 30 - 6*3 + 0.01 = 12.01
for t=3 and h=0.001
rc= 30 - 6*3 + 0.01 = 12.001
when h goes smaller , the average rate of change gets closer to the instantaneous rate of change of R(t) in t=3 (the derivative of R in t=3) , that is
R'(t)= 30 - 6*t
Answer :(A)
Step-by-step explanation:
