All categories

3 years ago

Algebra 2 help please

Mathematics

1 answer:

yan [13]3 years ago

4 0

Answer:

17. a) (4x - 8)(6x+ 7); b) 20x - 2

18. a) (2x² + 3x - 5)(2x + 3); b) 4x² + 10x - 4

Step-by-step explanation:

Question 17

a) Area

Area = length × width

A = (4x - 8)(6x+ 7)

b) Perimeter

Perimeter = 2 (length + width)

P = 2(4x - 8 + 6x + 7) = 2(10x - 1) = 20x - 2

Question 18

a) Area

A = (2x² + 3x - 5)(2x + 3)

b) Perimeter

P = 2(2x² + 3x - 5 + 2x + 3) = 2(2x² + 5x - 2) = 4x² + 10x - 4

You might be interested in

Idendify the slope and y-intercept from the equation below.

balandron [24]

M = 10
y = 10x-5. Hope it helppppppppppppppp

4 0

3 years ago

Read 2 more answers

Solve for c 4c+9d=16

Ad libitum [116K]

1 plus 1 =2

2+2 4 3+3 6 77÷11 7

8 0

2 years ago

Solve :3(2x+1)^-1 + 5x=-1<br>

Finger [1]

hope this is ans . Brother

8 0

2 years ago

See figure in triangle PQR,ANGLE PQR=90°,segQS seg PR find x,y and z

e-lub [12.9K]

Answer:

x=4√5

y=12

z=6√5

is your answer look it once

3 0

2 years ago

Triangle NMO has vertices at N(−5, 2), M(−2, 1), O(−3 , 3). Determine the vertices of image N′M′O′ if the preimage is reflected

Firdavs [7]

Notice that the reflection is over a line of the form x=constant; in this case, the y-coordinate of the reflected point stays the same while the x-coordinate changes as expressed by the transformation below

$\begin{gathered} y\rightarrow y \\ x\rightarrow2a+x \\ where \\ x=a\rightarrow\text{ vertical line} \end{gathered}$

Hence, in our case

$\Rightarrow(x,y)=(2*-4-x,y)=(-8-x,y)$

Transform points N, M, and O accordingly,

$\begin{gathered} \Rightarrow N^{\prime}=(-8-(-5),2)=(-8+5,2)=(-3,2) \\ \Rightarrow M^{\prime}=(-8-(-2),1)=(-6,1) \\ \Rightarrow O^{\prime}=(-8-(-3),3)=(-5,3) \end{gathered}$ <h2>Therefore, the answer is the first option (top to bottom)</h2>

6 0

10 months ago