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Soloha48 [4]
3 years ago
13

. What is the volume of the cylinder below? 1 PS 10 in. 30 in. ​

Mathematics
1 answer:
Anna11 [10]3 years ago
6 0
<h2><u>Answer:</u></h2><h2><u></u>\boxed{V=9424.8~in.}<u></u></h2><h2><u></u></h2><h2><u>Solution Steps:</u></h2>

______________________________

<h3><u> </u></h3><h3>1.) Find the formula:</h3>
  • <u>Cylinder Formula:</u> V= πr^2h
  • <u>Our Formula:</u> V= π10^230
<h3><u></u></h3><h3>2.) Solve the formula:</h3>
  • <u>Multiply by pi:</u> π × 10^2= 314.2
  • <u>Multiply the decimal by 30:</u> 314.2 × 30=9424.8
<h3 />

______________________________

<h3><u></u></h3>
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Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous plan
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Answer:

its 450 k

Step-by-step explanation:

It is given that the temperature of the gaseous planet is linearly related with height of the atmosphere. we can write this in the mathematical equation:

y = m x +c

where y is the temperature values, x is height, m is the slope and c is the y-intercept. we have been given two sets of value in the image, using which we can find the value of slope in y-intercept.

at x = 18.40 km, y = 147.54 K

⇒147.54 = 18.40 m + c      

⇒c = 147.54 - 18.40 m  ..(1)

at x =78.11 km, y = 567.00 K

⇒567.00 =78.11 m + c       ..(2)

Put equation 1 in 2 and solve:

⇒567.00 =78.11 m + 147.54 - 18.40 m

⇒419.46 = 59.71 m

⇒ m =419.46 ÷59.71 = 7.025 K/km

c = 147.54 - 18.40 × 7.025 = 18.28 K

At height, x = 61.5 km the approximate temperature is :

y = 7.025 K/km ×  61.5 km + 18.28 K = 450.3 K

Thus, the approximate temperature at altitude 61.5 km is 450 K.

7 0
3 years ago
The function C(x)=−15x+2304 represents the cost to produce x items. What is the least number of items that can be produced so th
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Answer:

152

Step-by-step explanation:

Given the function :

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The least Number of items, x that can be produced so that average cost does not exceed $33

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33 - 2304 = - 15x

-2271 = - 15x

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What is the midpoint between A and B?
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The diagram shows two nested triangles that share a vertex.Find a center and a scale factor for a dilation that would move the l
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Transformation that changes the size of a shape is referred to as dilation.

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<u>The center of dilation</u>

From the diagram (see attachment), the triangles share a common vertex at (-1,1)

This means that, the center of dilation is (-1,1)

<u>The scale factor of dilation</u>

To do this, we divide the side length of the small triangle with the corresponding side of the large triangle.

From the attached image:

\mathbf{Base\ of\ small\ triangle = 1}

\mathbf{Base\ of\ large\ triangle = 5}

So, the scale factor (k) from large to small is:

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\mathbf{k = \frac{1}{5} }

Read more about dilation at:

brainly.com/question/13176891

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