2 years ago

Find the area A of polygon TUVWXY with the given vertices.

1 answer:

8 0

The correct answer would be 9

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kondor19780726 [428]

Answer:

pre-existing cells

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san4es73 [151]

Answer:

you can use photomath or mathpapa

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2 years ago

Archy [21]

Answer:

A) perimeter = 3 + 3 + 8 + 8 = 22 units

B) area = 3 x 8 = 24 units²

Step-by-step explanation:

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2 years ago

12345 [234]

<span>4+6(7x+7)
= 4 + 42x + 42
= 42x + 46

hope it helps</span>

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3 years ago

Advocard [28]

The minimum of a quadratic function, with a positive coefficient a, is its vertex.

Let's find the x₀ coordinate.

$f(x) = 5x^2 -70x + 258\\\\x_0=\dfrac{-b}{2a}=\frac{-(-70)}{2*5} =\frac{70}{10} =7$

Now we need to find y₀ coordinate. That will be the minimum of function.

$y_0=5\times7^2-70\times7+258=13$

So, the minimum cost to produce the product is $13

Decompose 5x^2 − 70x + 258 into multipliers

$5x^2 - 70x + 258=(5x^2-70x+245)+13=5(x^2-14+49)+13=\\=5(x-7)^2+13$

Answer: 5(x − 7)^2 + 13; The minimum cost to produce the product is $13.

4 0

2 years ago