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3 years ago

6

Farmer Jenson has some geese and some goats. Between them they have 86 legs and 60 eyes. How many geese, and how many goats does

farmer Jenison have?

2 answers:

tester [92]3 years ago

6 0

All together you will get a mulitple of 146

musickatia [10]3 years ago

6 0

I'm replying late. But I know that some people need the answer. Your answer would be 13 goats and 17 geese.

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the distance around the outside of cedar park is 0.8 mile. Joanie ran 0.25 of the distance during her lunch break. How far did s

Natalija [7]

She ran 0.2 miles during her lunch break.

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3 years ago

Simplify the expression using the following values:<br> w=−4; v=5; u=2<br> 4w² − v + 3u

Grace [21]

Given:

w=-4
v=5
u=2

<u>Step</u><u> </u><u>by</u><u> step</u><u> explanation</u><u>:</u>

Step 1:

$4w² − v + 3u$

Step 2:

$= {4( - 4)}^{2} - 5 + 3 \times 2$

Step 3:

$= 4(16) - 5 + 6$

Step 4:

$= 64 - 5 + 6$

Step 5:

$= 64 + 1$

Step 6:

$= 65✓$

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4 years ago

If f(x)=x^2find f(2)-f(0)/2

alukav5142 [94]

Answer:

2

Step-by-step explanation:

On the picture above.

8 0

3 years ago

An individual repeatedly attempts to pass a driving test. Suppose that the probability of passing the test with each attempt is

vladimir1956 [14]

Answer:

a) Our random variable X="number of tests taken until the individual passes" follows a geomteric distribution with probability of success p=0.25

For this case the probability mass function would be given by:

$P(X= k) = (1-p)^{k-1} p , k = 1,2,3,...$

b) $P(X \leq 3) = P(X=1) +P(X=2) +P(X=3)$

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

And adding the values we got:

$P(X \leq 3) =0.25+0.1875+0.1406=0.578$

c) $P(X \geq 5) = 1-P(X$

And we can find the individual probabilities:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

$P(X= 4) = (1-0.25)^{4-1} *0.25 = 0.1055$

$P(X \geq 5) = 1-[0.25+0.1875+0.1406+0.1055]= 0.316$

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number of trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

Part a

Our random variable X="number of tests taken until the individual passes" follows a geomteric distribution with probability of success p=0.25

For this case the probability mass function would be given by:

$P(X= k) = (1-p)^{k-1} p , k = 1,2,3,...$

Part b

We want this probability:

$P(X \leq 3) = P(X=1) +P(X=2) +P(X=3)$

We find the individual probabilities like this:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

And adding the values we got:

$P(X \leq 3) =0.25+0.1875+0.1406=0.578$

Part c

For this case we want this probability:

$P(X \geq 5)$

And we can use the complement rule like this:

$P(X \geq 5) = 1-P(X$

And we can find the individual probabilities:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

$P(X= 4) = (1-0.25)^{4-1} *0.25 = 0.1055$

$P(X \geq 5) = 1-[0.25+0.1875+0.1406+0.1055]= 0.316$

3 0

3 years ago

Write 19/41 in lowest forms

Verizon [17]

Answer:

19/41

Step-by-step explanation:

this fraction cannot be simplified since 19 is a prime number.

5 0

3 years ago