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AveGali [126]
3 years ago
6

Farmer Jenson has some geese and some goats. Between them they have 86 legs and 60 eyes. How many geese, and how many goats does

farmer Jenison have?
Mathematics
2 answers:
tester [92]3 years ago
6 0
All together you will get a mulitple of 146
musickatia [10]3 years ago
6 0

I'm replying late. But I know that some people need the answer. Your answer would be 13 goats and 17 geese.

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Solve the system of equations.<br><br>x=y−9<br><br><br>8x−y=0<br><br><br>X=?<br><br>Y=?
Nataly [62]

Answer:

X = 9/7

Y = 72/7

Step-by-step explanation:

You need to subtract equation 1 by equation 2 to get rid of y. Then substitute your answer to find y.

3 0
3 years ago
The ratio of number of male and female teachers in a school is 3:4. Find the number of male teachers if there are 16 female teac
Alex_Xolod [135]

Answer:

12 male teachers

Step-by-step explanation:

If the ratio is 3:4, and the number of female teachers is 16, then the number of male teachers must be 12. This can be confirmed by multiplying both 3 and 4 by 4, or 12/16 = 3/4.

6 0
3 years ago
Read 2 more answers
A ​20-ft by ​the 40-ft rectangular swimming pool is surrounded by a walkway of uniform width. If the total area of the walkway i
Jlenok [28]
<h3>Answer:  2 feet</h3>

========================================================

Explanation:

x = width of the walkway in feet

This is some positive real number.

The dimension of 20 feet bumps up to 20+2x when adding on x from both directions. Similarly, the 40 ft dimension becomes 40+2x

Refer to the diagram below.

The 20 ft by 40 ft pool is surrounded by a larger rectangle that is 20+2x ft by 40+2x ft

The pool itself is 20*40 = 800 sq ft. Add on the walkway area to get 800+256 = 1056 sq ft.

-----------

Area = length*width

1056 = (20+2x)*(40+2x)

1056 = 20*40 + 20*2x + 2x*40 + 2x*2x ... FOIL rule

1056 = 800 + 40x + 80x + 4x^2

0 = 4x^2 + 40x + 80x + 800 - 1056

0 = 4x^2 + 120x - 256

4x^2 + 120x -  256 = 0

4(x^2 + 30x - 64) = 0

x^2 + 30x - 64 = 0

Let's use the quadratic formula to finish solving for x.

Plug in a = 1, b = 30, c = -64

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-30\pm\sqrt{(30)^2-4(1)(-64)}}{2(1)}\\\\x = \frac{-30\pm\sqrt{1156}}{2}\\\\x = \frac{-30\pm34}{2}\\\\x = \frac{-30+34}{2} \ \text{ or } \ x = \frac{-30-34}{2}\\\\x = \frac{4}{2} \ \text{ or } \ x = \frac{-64}{2}\\\\x = 2 \ \text{ or } \ x = -32\\\\

Recall we made x be positive. This is because a negative walkway width does not make sense. This means we'll ignore x = -32.

The only practical solution is x = 2

Therefore, the walkway is <u>2 feet wide</u>

4 0
2 years ago
Chip and Dale have 42 marbles. chip has six more marbles than Dale .how many marbles does Chip have
yaroslaw [1]
47 marbles if they each have 42 marbles
3 0
4 years ago
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Is the mean average number on these five cards is six what is the number on the bottom card. 7,8,5,2,_
netineya [11]
6×5=30. the sum of the five numbers is 30. then just do 30-7-8-5-2=8. 8 is the number on the bottom card.
5 0
4 years ago
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