825
Because when we did that we got
Answer: 1,045 passengers
Step-by-step explanation:
This question involves multiple steps. Let's first try to figure the number of children on the cruise.
The ratio of girls to the total number of children was 2:5. There are 198 boys.
This information tells me that for every 5 children, there's 2 girls and 3 boys.
Based off of this information, we can divide the total number of boys by 3 in order to find the number of children.
198÷3=66
Let's multiply 66 by 5 since that's the number of groupings based off the ratio.
66×5=330
Let's check the number of children. Since the ratio of girls to total children is 2:5 and we already confirmed there's 198 boys, there should be 132 girls. We can turn this ratio into a fraction where 2/5 of the children are girls. we can confirm this by multiply 330 by 2/5 (0.4) and getting 132.
There are 330 children on the cruise.
The ratio of the number of adults to the number of children was 13:6.
For every 6 children, there were 13 adults. Let's divide the number of children by 6 in order to find the number of groupings.
330÷6=55
Let's now multiply the groupings by 13 to find the number of adults.
55×13=715
So there should be 715 adults and 330 children on the cruise.
715+330=1,045
Answer:
Total distance traveled = 56 m
Total displacement is 12 m
Direction of coach is westward
Step-by-step explanation:
It is given that football coach first go 12 meter westward then 16 meter eastward.
So no position of coach in eastward direction = 16 - 12 = 4 m
And then 22 m west westward
Therefore position of coach now is 22-4 = 18 m westward
And finally 6 m eastward
Therefore final position of coach is 18-6= 12 m westward
So displacement of coach is 12 m and direction is westward.
Total distance traveled = 12+16+22+6= 56 m
The speed of wind and plane are 105 kmph and 15 kmph respectively.
<u>Solution:</u>
Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.
We have to find the air speed of the plane and speed of the wind.
Now, let the speed wind be "a" and speed of aeroplane be "b"
And, we know that, distance = speed x time.
Now at head wind → 
So, solve (1) and (2) by addition
2a = 210
a = 105
substitute a value in (1) ⇒ 105 + b = 120
⇒ b = 120 – 105 ⇒ b = 15.
Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.
Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.
