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2 years ago

Write the equation of the line in slope-intercept form given the graph below.

Mathematics

2 answers:

belka [17]2 years ago

6 0

Answer:

y=-2/3x-1

Step-by-step explanation:

pishuonlain [190]2 years ago

4 0

Answer:

y=-2/3x-1

Step-by-step explanation:

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Please help me out!!!!!!!!!!!!!!!!!!<br>true or false

garri49 [273]

It is possible to have a triangle with those lengths

6 0

3 years ago

A random experiment was conducted where a Person A tossed five coins and recorded the number of ""heads"". Person B rolled two d

cestrela7 [59]

Answer:

(10) Person B

(11) Person B

(12) $P(5\ or\ 6) = 60\%$

(13) Person B

Step-by-step explanation:

Given

Person A $\to$ 5 coins (records the outcome of Heads)

Person $\to$ Rolls 2 dice (recorded the larger number)

Person A

First, we list out the sample space of roll of 5 coins (It is too long, so I added it as an attachment)

Next, we list out all number of heads in each roll (sorted)

$Head = \{5,4,4,4,4,4,3,3,3,3,3,3,3,3,3,3,2,2,2,2,2,2,2,2,2,2,1,1,1,1,1,0\}$

$n(Head) = 32$

Person B

First, we list out the sample space of toss of 2 coins (It is too long, so I added it as an attachment)

Next, we list out the highest in each toss (sorted)

$Dice = \{2,2,3,3,3,3,4,4,4,4,4,4,5,5,5,5,5,5,5,5,6,6,6,6,6,6,6,6,6,6\}$

$n(Dice) = 30$

Question 10: Who is likely to get number 5

From person A list of outcomes, the proportion of 5 is:

$Pr(5) = \frac{n(5)}{n(Head)}$

$Pr(5) = \frac{1}{32}$

$Pr(5) = 0.03125$

From person B list of outcomes, the proportion of 5 is:

$Pr(5) = \frac{n(5)}{n(Dice)}$

$Pr(5) = \frac{8}{30}$

$Pr(5) = 0.267$

<em>From the above calculations: </em> $0.267 > 0.03125$ <em> Hence, person B is more likely to get 5</em>

Question 11: Person with Higher median

For person A

$Median = \frac{n(Head) + 1}{2}th$

$Median = \frac{32 + 1}{2}th$

$Median = \frac{33}{2}th$

$Median = 16.5th$

This means that the median is the mean of the 16th and the 17th item

So,

$Median = \frac{3+2}{2}$

$Median = \frac{5}{2}$

$Median = 2.5$

For person B

$Median = \frac{n(Dice) + 1}{2}th$

$Median = \frac{30 + 1}{2}th$

$Median = \frac{31}{2}th$

$Median = 15.5th$

This means that the median is the mean of the 15th and the 16th item. So,

$Median = \frac{5+5}{2}$

$Median = \frac{10}{2}$

$Median = 5$

<em>Person B has a greater median of 5</em>

Question 12: Probability that B gets 5 or 6

This is calculated as:

$P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}$

From the sample space of person B, we have:

$n(5\ or\ 6) =n(5) + n(6)$

$n(5\ or\ 6) =8+10$

$n(5\ or\ 6) = 18$

So, we have:

$P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}$

$P(5\ or\ 6) = \frac{18}{30}$

$P(5\ or\ 6) = 0.60$

$P(5\ or\ 6) = 60\%$

Question 13: Person with higher probability of 3 or more

Person A

$n(3\ or\ more) = 16$

So:

$P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Head)}$

$P(3\ or\ more) = \frac{16}{32}$

$P(3\ or\ more) = 0.50$

$P(3\ or\ more) = 50\%$

Person B

$n(3\ or\ more) = 28$

So:

$P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Dice)}$

$P(3\ or\ more) = \frac{28}{30}$

$P(3\ or\ more) = 0.933$

$P(3\ or\ more) = 93.3\%$

By comparison:

$93.3\% > 50\%$

Hence, person B has a higher probability of 3 or more

7 0

2 years ago

A population of geese grow in such a way that each generation is simply 2.2 times the previous generation. There were 3 geese in

lapo4ka [179]

First generation: 3

Second generation: $3\times2.2$

Third generation: $3\times2.2\times2.2=3\times2.2^2$

Fourth generation: $3\times2.2\times2.2\times2.2=3\times2.2^3$

And so on. The general formula for the $n$ th generation is $3\times2.2^{n-1}$ . So by the 15th generation, you should expect around $3\times2.2^{15-1}\approx186655$ geese.

5 0

3 years ago

Read 2 more answers

What other information do you need in order to prove the triangles congruent using the SAS congruence postulate

iren [92.7K]

AC is perpendicular to BD.

<h3>Further explanation</h3>

We observe that both the ABC triangle and the ADC triangle have the same AC side length. Therefore we know that $\boxed{ \ \overline{AC} \cong \overline{AC} \ }$ is reflexive.
The length of the base of the triangle is the same, i.e., $\boxed{ \ \overline{BC} = \overline{CD} \ }$ .
In order to prove the triangles congruent using the SAS congruence postulate, we need the other information, namely $\boxed{ \ AC \bot BD \ }$ . Thus we get ∠ACB = ∠ACD = 90°.

Conclusions for the SAS Congruent Postulate from this problem:

$\boxed{ \ \overline{BC} = \overline{CD} \ }$
∠ACB = ∠ACD
$\boxed{ \ \overline{AC} = \overline{AC} \ }$

- - - - - - - - - -

The following is not other or additional information along with the reasons.

∠CBA = ∠CDA no, because that is AAS with ∠ACB = ∠ACD and $\boxed{ \ \overline{AC} \cong \overline{AC} \ }$
∠BAC = ∠DAC no, because that is ASA with $\boxed{ \ \overline{AC} \cong \overline{AC} \ }$ and ∠ACB = ∠ACD.
$\boxed{ \ \overline{BC} = \overline{CD} \ }$ no, because already marked.

- - - - - - - - - -

Notes

The SAS (Side-Angle-Side) postulate for the congruent triangles: two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle; the included angle properly represents the angle formed by two sides.
The ASA (Angle-Side-Angle) postulate for the congruent triangles: two angles and the included side of one triangle are congruent to two angles and the included side of another triangle; the included side properly represents the side between the vertices of the two angles.
The SSS (Side-Side-Side) postulate for the congruent triangles: all three sides in one triangle are congruent to the corresponding sides within the other.
The AAS (Angle-Angle-Side) postulate for the congruent triangles: two pairs of corresponding angles and a pair of opposite sides are equal in both triangles.

<h3>Learn more</h3>

Which shows two triangles that are congruent by ASA? brainly.com/question/8876876
Which shows two triangles that are congruent by AAS brainly.com/question/3767125
About vertical and supplementary angles brainly.com/question/13096411

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3 years ago

Read 2 more answers

This number is in scientific notation. 2. 4 × 10-4 Convert the number into standard notation. What is the value? 2. 4 × 10-4 =.

Dimas [21]

2.4x10^-4 = 0.00024

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1 year ago