Answer:
<em>-21 and 4</em>
Step-by-step explanation:
They multiply to a negative number, so you need a positive number and a negative number.
<span>You are given the word alabama and you are asked to find how many distinguishable 7 letter "words" can be formed from it.
ALABAMA has seven letters so we will start at 7!
Counting the number of A's in the word we have 4 A's and so we will divide it by 4!
</span>Counting the number of L's in the word we have 1 L and so we will divide it by 1!
Counting the number of B's in the word we have 1 B and so we will divide it by 1!
Counting the number of M's in the word we have 1 M and so we will divide it by 1!
And so the number of ways is 7! / (4! x 1! x 1! x 1!) = 210 words.
Yes it can. It doesn't <em>have to be</em>, but it can be without too much trouble.
In fact, ALL rhombuses are quadrilaterals.
A
Because i did the math and i had this question before
65/3=21 with 2 leftover
(2/3)/3 or 2/3•1/3 = 2/9
so either they didn’t get to share or each got 2/9 of the leftovers
