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White raven [17]
3 years ago
12

how can you copy a angle using a straightedge, a compass, and a pencil, give step by step instructions

Mathematics
2 answers:
Murljashka [212]3 years ago
8 0

Start with a angle BAC that we will copy.
1. Make a point P that will be the vertex of the new angle.
2. From P, draw a ray PQ. This will become one side of the new angle.

This ray can go off in any direction.
It does not have to be parallel to anything else.
It does not have to be the same length as AC or AB.

3. Place the compasses on point A, set to any convenient width.
4. Draw an arc across both sides of the angle, creating the points J and K as shown.
5. Without changing the compasses' width, place the compasses' point on P and draw a similar arc there, creating point M as shown.
6. Set the compasses on K and adjust its width to point J.
7. Without changing the compasses' width, move the compasses to M and draw an arc across the first one, creating point L where they cross.
8. Draw a ray PR from P through L and onwards a little further. The exact length is not important.
Done. The angle ∠RPQ is congruent (equal in measure) to angle ∠BAC.
MissTica3 years ago
6 0

Answer:

Step-by-step explanation: Draw a working line, l, with point B on it.

Open your compass to any radius r, and construct arc (A, r) intersecting the two sides of angle A at points S and T.

Construct arc (B, r) intersecting line l at some point V.

Construct arc (S, ST).

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The solution set of 4x-(x+7)=2(x+3)​
maria [59]

Step-by-step explanation:

<h3><u>To</u><u> </u><u>Solve</u><u>:</u><u>-</u></h3>

\\ \tt{:}\leadsto 4x-(x+7)=2(x+3)

<h3><u>SOL</u><u>UTION</u><u>:</u><u>-</u></h3>

\\ \tt{:}\leadsto 4x-(x+7)=2(x+3)

\\ \tt{:}\leadsto 4x-x-7=2x+6

\\ \tt{:}\leadsto 3x-7=2x+6

\\ \tt{:}\leadsto 3x-2x=6+7

\\ \tt{:}\leadsto x=13

7 0
3 years ago
Rent and other associated housing costs, such as utilities, are an important part of the estimated costs of attendance at colleg
zhenek [66]

Answer:

96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is  [335.89 , 356.10].

Step-by-step explanation:

We are given that a group of researchers at the BYU Off-Campus Housing department want to estimate the mean monthly rent that unmarried BYU students paid during winter 2018.

During March 2018, they randomly sampled 314 BYU students and found that on average, students paid $346 for rent with a standard deviation of $86.

So, the pivotal quantity for 95% confidence interval for the average age is given by;

           P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = average rent paid by 314 BYU students = $346

            s = sample standard deviation = $86

            n = sample of students = 314

            \mu = population mean monthly rent of all unmarried BYU students

So, 96% confidence interval for the population mean monthly rent, \mu is ;

P(-2.082 < t_3_1_3 < 2.082) = 0.96

P(-2.082 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.082) = 0.96

P( -2.082 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.082 \times {\frac{s}{\sqrt{n} } } ) = 0.96

P( \bar X -2.082 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X +2.082 \times {\frac{s}{\sqrt{n} } } ) = 0.96

96% confidence interval for \mu = [ \bar X -2.082 \times {\frac{s}{\sqrt{n} } } , \bar X +2.082 \times {\frac{s}{\sqrt{n} } } ]

                                                = [ 346 -2.082 \times {\frac{86}{\sqrt{314} } } , 346 +2.082 \times {\frac{86}{\sqrt{314} } } ]

                                                = [335.89 , 356.10]

Therefore, 96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].

5 0
4 years ago
What is the area of the square? A square with the left side labeled 4 units.
Liono4ka [1.6K]
Area of square is a^2
4^2 = 16
the area is 16 units
7 0
3 years ago
Read 2 more answers
PLEASE HELP ME what is the solution to the system of equations?
masha68 [24]
Times the bottom equation by -4 to cancel out the x’s.
Add the equations.
Solve for y.
Plug in y to find x.

8 0
3 years ago
In an arithmetic sequence, if a2= 5 and a10= 19 find a6
OLEGan [10]

Answer:

a₆ = 12

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₂ = 5 and a₁₀ = 19 , then

a₁ + d = 5 → (1)

a₁ + 9d = 19 → (2)

Subtract (1) from (2) term by term to eliminate a₁

8d = 14 ( divide both sides by 8 )

d = 1.75

Substitute d = 1.75 into (1)

a₁ + 1.75 = 5 ( subtract 1.75 from both sides )

a₁ = 3.25

Then

a₆ = 3.25 + 5(1.75) = 3.25 + 8.75 = 12

6 0
3 years ago
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