2 years ago

What is an equation of the line that passes through the point (-6, – 7) and is perpendicular to the line 6x + 5y = 30?

Mathematics

1 answer:

fomenos2 years ago

3 0

Answer :6x + 5y = 30

5y = 30 - 6x

y = 6 - (6/5) x

So slope = -6/5

Perpendicular line has slope 5/6 (product of the slopes is -1)

So y = 5/6 x + b

Passed through (-6, -7) so -7 = -5 + b

Sp b = -2

So y = (5/6)x - 2

Step-by-step explanation:

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