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3 years ago

15

Find the descriminant? forgot how.

2 answers:

ivanzaharov [21]3 years ago

8 0

In a quadratic equation, the discriminant<span> helps tell you the number of real solutions to a quadratic equation. The expression used to </span>find the discriminant<span> is the expression located under the radical in the quadratic formula!</span>

Ilia_Sergeevich [38]3 years ago

5 0

I hope this helps you

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If T is the point at the given distance on the unit circle C from P (1, 0), determine the quadrant in which T lies:

givi [52]

Hello,

Answer D

9π/6<11π/6<12π/6
Quadrant IV

8 0

3 years ago

Read 2 more answers

2(1 − x) = 9(1 + 2x) + 52(1 − x) = 9(1 + 2x) + 5

marusya05 [52]

Solving the equation $2(1-x) = 9(1 + 2x) + 5$ we get $x=-\frac{3}{5}$

Step-by-step explanation:

We need to solve the equation $2(1-x) = 9(1 + 2x) + 5$ and find value of x

Solving:

$2(1-x) = 9(1 + 2x) + 5\\2-2x=9+18x+5\\Adding\,\,-18x\,\,on\,\,both\,\,sides:\\2-2x-18x=9+5\\Adding\,\,-2\,\,on\,\,both\,\,sides\\-20x=14-2\\-20x=12\\x=\frac{12}{-20}\\x=-\frac{3}{5}$

So, solving the equation $2(1-x) = 9(1 + 2x) + 5$ we get $x=-\frac{3}{5}$

Keywords: Solving Equations

Learn more about Solving Equations at:

#learnwithBrainly

7 0

3 years ago

5. Please write the equation of a line in y=mx+b format. Find the SLOPE first then find the Y-INTERCEPT (b) Your answer

castortr0y [4]

Answer:

y = $\frac{5}{3}x-1$

Step-by-step explanation:

Let the equation of the line is,

y = mx + b

Here m = slope of the line

b = y-intercept

Slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is,

m = $\frac{y_2-y_1}{x_2-x_1}$

From the graph attached,

Since, the given line passes through (0, -1) and (3, 4),

Slope 'm' = $\frac{4+1}{3-0}$

m = $\frac{5}{3}$

y - intercept 'b' = -1

Therefore, equation of the line will be,

y = $\frac{5}{3}x-1$

5 0

3 years ago

If there are 36 inches in 1 yard, convert 82 inches to yards.

Lunna [17]

82/36 = 2 10/36 = 2 5/18

3 0

3 years ago

Through (-4,3) , perpendicular to m=-2/3

stiv31 [10]

Answer:

The equation of the line:

$y=\frac{3}{2}x+9$

Step-by-step explanation:

Given

The point (-4, 3)

m = -2/3

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

slope = m = -2/3

perpendicular to m = -1/m

$=-\frac{1}{\left(\frac{-2}{3}\right)}=\frac{3}{2}$

Using the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 3/2 and the point (-4, 3)

$y-3=\frac{3}{2}\left(x-\left(-4\right)\right)$

$y-3=\frac{3}{2}\left(x+4\right)$

Add 3 to both sides

$y-3+3=\frac{3}{2}\left(x+4\right)+3$

$y=\frac{3}{2}x+9$

Thus, the equation of the line:

$y=\frac{3}{2}x+9$

5 0

3 years ago