Take the derivative:
g’(x) = 12x^3 - 24x^2
Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)
x = 0 or x = 2
Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0
g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52
There is an absolute max at (0,0) or when x = 0
Answer:
x=1
Step-by-step explanation:
A. You can use y=mx+b to find the rate of change of a bushel corn in the current year. The rate of change would be y=8x.
B. One bushel is worth 8$ (24/3 = 8) in the current year, and in the previous year one bushel was worth 7$ (21/3= 7). Therefore there was a 1$ raise from the previous year to the current year.
