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3 years ago

12

PLEASE HELP ME!!

1 answer:

Grace [21]3 years ago

5 0

Take the derivative:
g’(x) = 12x^3 - 24x^2

Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)

x = 0 or x = 2

Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0

g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52

There is an absolute max at (0,0) or when x = 0

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4 years ago

(2x105)/(3x103) + 3x103 * 5x102

AleksAgata [21]

Answer:

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Step-by-step explanation:

Given: $(2\times10^{5} )/(3\times 10^{3} ) + 3\times10^{3} \times 5\times10^{2}$

Now, simplifying it.

Using PEDMAS in solving the expression

First opening the parenthesis

= $2\times10^{5} /3\times 10^{3} + 3\times10^{3} \times 5\times10^{2}$

Next dividing the number

as per law of indices, $x^{m} \div x^{n} = x^{m-n}$

= $2\times10^{5-3} /3 + 3\times10^{3} \times 5\times10^{2}$

= $2\times10^{2} /3 + 3\times10^{3} \times 5\times10^{2}$

= $\frac{2\times10^{2} }{3} + 3\times10^{3} \times 5\times10^{2}$

Next multiplying the number as per PEDMAS

as per law of indices, $x^{m} \times x^{n} = x^{m+n}$

= $\frac{2\times10^{2} }{3} + 15\times10^{3+2}$

= $\frac{2\times10^{2} }{3} + 15\times10^{5}$

= $\frac{2\times 100}{3} + 15\times10^{5}$

Next dividing the number as per PEDMAS

= $2\times 33.33 + 15\times10^{5}$

Next multiplying the number as per PEDMAS

= $66.66+1500000$

Now adding the number

= 1500066.66

4 0

3 years ago