11) First, add 74 and 43.
74+43=117
Subtract 117 from 180. Do this because this will give you the value of angle 1. This is because the sum of the angles in a triangle will always add up to 180 degrees.
180-117=63
Angle 1 = 63 degrees
Angle 2 also equals 63 degrees, because they are vertical angles.
Angle 2= 63 degrees
Now, add 63 and 79
63+79=142
Subtract 142 from 180
180-142=38
Angle 3 = 38 degrees
12)
First, subtract 56 from 180. Do this to find angle C. They are supplementary angles, so they will equal 180 degrees.
180-56=124
Angle C=124 degrees
Now, add 124 and 20
124+20=144
Finally, subtract 144 from 180
180-144=36
The measure of angle A is 36 degrees
Hope this helped! :)
Answer:
x = 15.7945
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] sinθ = opposite over hypotenuse
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
Angle θ = 33°
Opposite Leg = <em>x</em>
Hypotenuse = 29
<u>Step 2: Find Angle</u>
- Substitute in variables [sine]: sin33° = x/29
- [Multiplication Property of Equality] Multiply 29 on both sides: 29sin33° = x
- Rewrite: x = 29sin33°
- Evaluate: x = 15.7945
The answer is D. 18.5
How? Because you have the numbers in order and cross the out it leaves you with 17, and 20 and the number between can be 19 or 18.5.
Hope I helped
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Answer:
Choose a point with a negative x coordinate and a positive y coordinate.
Step-by-step explanation:
The quadrants are labeled counter clockwise 1, 2, 3, and 4.
Quadrant I - has x and y coordinate both positive.
Quadrant 2 - has x coordinate negative and y coordinates positive.
Quadrant 3 - has x and y coordinates both negative.
Quadrant 4 - has x coordinates positive and y coordinates negative.
Since the point is in quadrant 2, choose a point where x is negative but y is positive like (-3, 2).
