Answer:
There is no unique solution to this problem.
There are infinitely many solutions to this problem.
Step-by-step explanation:
Let B denotes broccoli crop
Let S denotes spinach crop
Last year, he grew 6 tons of broccoli per acre and 9 tons of spinach per acre, for a total of 93 tons of vegetables.
Mathematically,
6B + 9S = 93 eq. 1
This year, he grew 2 tons of broccoli per acre and 3 tons of spinach per acre, for a total of 31 tons of vegetables.
Mathematically,
2B + 3S = 31
2B = 31 - 3S
B = (31 - 3S)/2 eq. 2
Substitute eq. 2 into eq. 1
6B + 9S = 93
6[(31 - 3S)/2] + 9S = 93
3(31 - 3S) + 9S = 93
93 - 9S + 9S = 93
- 9S + 9S = 93 - 93
0 = 0
Therefore, there is no unique solution to this problem.
Which means that there are infinitely many solutions to this problem.
Use the trig identity
2*sin(A)*cos(A) = sin(2*A)
to get
sin(A)*cos(A) = (1/2)*sin(2*A)
So to find the max of sin(A)*cos(A), we can find the max of (1/2)*sin(2*A)
It turns out that sin(x) maxes out at 1 where x can be any expression you want. In this case, x = 2*A.
So (1/2)*sin(2*A) maxes out at (1/2)*1 = 1/2 = 0.5
The greatest value of sin(A)*cos(A) is 1/2 = 0.5
Answer:
B
Step-by-step explanation:
Your answer is 28 because 4/7 turn it to a decimal and then divide 8 from it and that is how you get your answer 28.
Hope this helps:)
Pls mark brainlist
Would it be B which is 51%
as you do 129 devided by 3.3 = 39.1
180-39.1= 141
141 is just over half
