Just want you check if my answer is right...i'm not good in math.
1 answer:
You might be interested in
Answer: The 90% confidence interval for the population mean μ is between 82.85 and 85.15,
Step-by-step explanation:
When population standard deviation is not given ,The confidence interval population proportion is given by ( ):-
, where n= Sample size.
s= Sample standard deviation
= sample mean
t* = Critical t-value (Two-tailed)
As per given , we have
n= 64
Degree of freedom : df = n-1=63
s= 5.5
Significance level :
Two-tailed T-value for df = 63 and would be
(By t-distribution table)
i.e. t*= 1.669
The 90% confidence interval for the population mean μ would be
∴ The 90% confidence interval for the population mean μ is between 82.85 and 85.15,
ffn
the sum of their squares is 110, So
the sum of their cubes is 684, so
the product of the three integers is 210, so xyz= 210
the sum of any two products (xy+yz+zx) is 107
Now we plug in all the values in the identity
684 - 3(210) = (x+y+z)(110-107)
684 - 630 = (x+y+z)(3)
54 = 3(x+y+z)
Divide by 3 on both sides
18 = x+y+z
the value of the sum of three integers is 18