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miss Akunina [59]

2 years ago

9

help help help help help help help help help help help help help help help help help help help help help help help help help hel

p help

2 answers:

wel2 years ago

8 0

the answer its -3/2

marshall27 [118]2 years ago

5 0

Answer:

..............................................................................................................

Step-by-step explanation:

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A large company claims that the average age of their employees is 32 years, with a standard deviation of 4 years. The average ag

4vir4ik [10]

Given that average age of employees of a large company is Normal

X - average age of employees

X:N(32,4)

The average age of employees in sales dept is 27 years.

Prob that an employee, chosen at random, will be younger than 27 years.

= P(X<27)

Let us convert x into Z

Z = (x-32)/4 = -5/4 = -1.25

Reqd prob = P(Z<-1.25) =0.5-0.3925

= 0.1075

Hence 10.56% is the correct answer.

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3 years ago

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What steps would you take to determine if these figures are similar? Check all that apply. Use a scale factor of 2. Multiply the

skad [1K]

Answer:

Well I took it"s Reflect the intermediate image. and Multiply the vertices of polygon ABCD by One-half.

Step-by-step explanation:

3 0

3 years ago

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If a = 5, b = 4, and c = 7, find the value for 3(b + a) = c.<br> 10<br> 15<br> 34<br> 20

Debora [2.8K]

Answer:

20

Step-by-step explanation:

3 (b + a) = c

3 (4 + 5) = 7

12 + 15 = 7

27 = 7

27 - 7

20

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3 years ago

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The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a

Anettt [7]

Answer:

1) The size of the colony after 4 days is 6553 mosquitoes

2) After $t = 4.9\ days$

Step-by-step explanation:

To answer this question you must use the growth formula

$N = N_0e ^ {kt}$

Where

$N_0$ is the initial population of mosquitoes = 1000

t is the time in days

k is the growth rate

N is the population according to the number of days

We know that when t = 1 and $N_0=1000$ then N = 1600

Then we use these values to find k.

$1600 = 1000e ^{k(1)}\\\\\frac{1600}{1000} = e ^ k\\\\ln(\frac{1600}{1000}) = k\\\\k = 0.47$

Now that we know k we can find the size of the colony after 4 days.

$N = 1000e ^ {0.47(4)}\\\\N = 6553\ mosquitoes$

To know how long it should take for the population to reach 10,000 mosquitoes we must do N = 10000 and solve for t.

$10000 = 1000e ^ {0.47t}\\\\10 = e ^ {0.47t}\\\\ln(10) = 0.47t\\\\t = \frac{ln(10)}{0.47}\\\\t = 4.9\ days$

6 0

2 years ago

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LenKa [72]

Answer:

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2 years ago