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777dan777 [17]
2 years ago
8

Find the arc length of the partial circle.

Mathematics
1 answer:
Sliva [168]2 years ago
6 0

Answer:

1/2pi

Step-by-step explanation:

Since the formula for circumference is 2*pi*r and we know the R=1 so the of the whole circle is 2pi. This is a quarter of a circle so the answer is 1/2pi  

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Evaluate 7j+5-8k when j=0.5 and k=0.25
dlinn [17]

So first you would substitute j and k in the expression.

7(0.5)+5-8(0.25)

3.5+5-2

It would equal 6.5

Hope this helps!

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Maria buys a one liter soda bottle She accidentally drops the soda bottle and spills 437 millimeters of soda How many soda is le
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3 kilograms of red hots and I
MrRa [10]

Answer:

Step-by-step explanation:

each kilogram of gummy bears is 9 dollars because the difference of 39 and 21 is 18, 18/2 is 9, 21-9=12 12/3=4 , therefor each kilogram of red hots is $4.00

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365x + 125 = 250x + 175
maxonik [38]
First, set up the equation. 
365x + 125 = 250x + 175 

Second, combine like terms on the same side by subtracting 250x and 125 from both sides.

365x +125 = 250x + 175  
-250x  -125   -250x -125 
__________________
115x = 50

Third, divide both sides by 115 to solve for x.

115x = 50
----      ----
115     115 

Fourth, simplify. 

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7 0
3 years ago
In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th
olya-2409 [2.1K]

Answer:

\frac{BE}{EC} =\frac{1}{3}

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

\frac{BK}{CK} =\frac{1}{4}

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE                ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE     ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK  and Δ EBK are similar

so we have

\frac{AD}{BE} =\frac{DK}{BK}

\frac{AD}{BE} =\frac{4}{1}

\frac{BC}{BE}=\frac{4}{1}     ( ABCD is parallelogram so AD=BC)

\frac{BE+EC}{BE}=\frac{4}{1}         ( BC= BE+EC)

\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}

1+\frac{EC}{BE}=4

\frac{EC}{BE}=3  ( subtracting 1 from both side )

\frac{EC}{BE}=\frac{3}{1}

taking reciprocal both side

\frac{BE}{EC} =\frac{1}{3}


8 0
3 years ago
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