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2 years ago

Find the arc length of the partial circle.

Mathematics

1 answer:

Sliva [168]2 years ago

6 0

Answer:

1/2pi

Step-by-step explanation:

Since the formula for circumference is 2*pi*r and we know the R=1 so the of the whole circle is 2pi. This is a quarter of a circle so the answer is 1/2pi

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In isosceles △ABC the segment BD (with D∈ AC ) is the median to the base AC . Find BD, if the perimeter of △ABC is 50m, and the

Morgarella [4.7K]

Let the equal sides of the isosceles Δ ABC be x.

Given that the perimeter of Δ ABC = 50m.

Therefore, 2x + AC = 50 --- (1)

It is also given that the perimeter of Δ ABD = 40m.

Therefore, x + BD + AD = 40

BD is the median of the Δ ABC. Therefore, D is the midpoint of AC.

So AD = CD.

Or, AD = $\frac{1}{2}$ AC

Therefore, $x + BD + \frac{1}{2} AC = 40$

Multiply both sides by 2.

2x + 2BD + AC = 80

From (1), 2x + AC = 50.

Therefore, 2BD + 50 = 80

2BD = 80 - 50

2BD = 30

BD = 15m.

6 0

3 years ago

Read 2 more answers

What is 10.4% as a fraction?

AlladinOne [14]

10.4% as a fraction is 104/1000

6 0

3 years ago

2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of

IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., $\mu$ = 35 and $\sigma$ = 6. We know that the probability density function for a normal distribution with a mean of $\mu$ and a standard deviation of $\sigma$ is given by

$f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]$

in this case we have

$f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]$

Let $X$ be the random variable that represents a row score, we find the values we are seeking in the following way

a) we are looking for a number $x_{0}$ such that

$P(X\leq x_{0})$ = $\int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65$ , this number is $x_{0}$ =37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number $x_{1}$ such that

$P(X\leq x_{1})$ = $\int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9$ , this number is $x_{1}$ =42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

$P(28\leq X\leq 38)$ = $\int\limits^{38}_{28} {f(x)} \, dx = 0.57$

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

$P(41\leq X\leq 44)$ = $\int\limits^{44}_{41} {f(x)} \, dx = 0.09$

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

6 0

3 years ago

Read 2 more answers

Help please look below

Gwar [14]

A is located, as you look A is past -2 almost hitting -3 making the mark 2.8 so the answer is A

3 0

2 years ago

if alyssa plans to run 7/8 mile on a trail at one point she sees that she is at mile maker 0.3 How much farther does she have to

Sever21 [200]

Rewrite 7/8 as a decimal by dividing 7 by 8:

7/8 = 0.875

Now to find how much further she has to run subtract where is now from the total distance:

0.875 - 0.3 = 0.575

She needs to run 0.575 miles more

6 0

2 years ago