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3 years ago

Find the arc length of the partial circle.

Mathematics

1 answer:

Sliva [168]3 years ago

6 0

Answer:

1/2pi

Step-by-step explanation:

Since the formula for circumference is 2*pi*r and we know the R=1 so the of the whole circle is 2pi. This is a quarter of a circle so the answer is 1/2pi

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The area of a bulletin board is 52 square feet. The length is 3 feet less than4 times the width. Find the length and width

Brilliant_brown [7]

Answer:

The length of the bulletin board is $13\ ft$

The width of the bulletin board is $4\ ft$

Step-by-step explanation:

Let

x-----> the length of the bulletin board

y-----> the width of the bulletin board

we know that

The area of the rectangle (bulletin board) is equal to

$A=xy$

we have

$A=52\ ft^{2}$

$52=xy$ ------> equation A

$x=4y-3$ ------> equation B

substitute equation B in equation A and solve for y

$52=(4y-3)y$

$4y^{2}-3y-52=0$

Using a graphing calculator------> solve the quadratic equation

The solution is

$y=4\ ft$

see the attached figure

Find the value of x

$x=4(4)-3=13\ ft$

6 0

4 years ago

I NEED HELP ALSO LEAVE YALL NUMBER BELOW IF UR 14+

Alexus [3.1K]

Come on bro you are way too young for that

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3 years ago

Which number is most likely an irrational number?

Eduardwww [97]

It would be D because it’s a non repeating decimal

8 0

3 years ago

Read 2 more answers

Write the expression 2i^15-i^7 in the standard form a + bi

elixir [45]

$\bf 2i^{15}-i^7\qquad 
\begin{cases}
i^2=\sqrt{-1}\cdot \sqrt{-1}\implies \sqrt{(-1)^2}\implies -1\\\\
i^4=i^2\cdot i^2\implies -1\cdot -1\implies 1
\end{cases}\\\\
-----------------------------\\\\
2i^{4+4+4+2+1}-i^{4+2+1}\implies 2i^4i^4i^4i^2i^1-i^4i^2i^1
\\\\\\
(2\cdot 1\cdot 1\cdot 1\cdot -1\cdot i)-(1\cdot -1\cdot i)\implies -2i-(-i)
\\\\\\
-2i+i\implies -i\implies \boxed{0-i}$

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3 years ago

Is 3/5 mile closer than 1/2 mile

Romashka [77]

Yes to both, and for future help, if you find a common denominator(the bottom one) by multiplication and one is higher, boom you have your answer.

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4 years ago