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777dan777 [17]
3 years ago
8

Find the arc length of the partial circle.

Mathematics
1 answer:
Sliva [168]3 years ago
6 0

Answer:

1/2pi

Step-by-step explanation:

Since the formula for circumference is 2*pi*r and we know the R=1 so the of the whole circle is 2pi. This is a quarter of a circle so the answer is 1/2pi  

You might be interested in
Which number line models the solution set of -2x + 7 > 17?
Darina [25.2K]

Answer:

-5

Step-by-step explanation:

-2x+7>17

-2x>17-7

-2x>10

Divide both sides by -2

-2x<10

-2 -2

x<-5

Note:when dividing with a negative the signs changes

7 0
3 years ago
Read 2 more answers
A cylinder has diameter of 4ft and a height of 9ft. Explain whether halving the diameter has the same effect on the surface area
elena55 [62]

Answer:

See Below

Step-by-step explanation:

The surface area of cylinder is given by the formula:

SA=2\pi r^2 + 2\pi r h

Where

r is radius ( diameter is 4, so radius is 4/2 = 2)

h is height ( h = 9)

Lets find original surface are:

SA=2\pi r^2 + 2\pi r h\\SA=2\pi (2)^2 + 2\pi (2) (9)\\SA=8\pi +36\pi\\SA=44\pi

<u>Halving diameter:</u>

diameter would be 4/2 = 2, so radius would be 2/2 = 1

So, SA would be:

SA=2\pi r^2 + 2\pi r h\\SA=2\pi (1)^2 + 2\pi (1) (9)\\SA=2\pi +18\pi\\SA=20\pi

<u>Halving height:</u>

Height is 9, halving would make it 9/2 = 4.5

Now, calculating new SA:

SA=2\pi r^2 + 2\pi r h\\SA=2\pi (2)^2 + 2\pi (2) (4.5)\\SA=8\pi + 18\pi\\SA= 26\pi

Original SA is 44\pi,

Halving diameter makes it 20\pi

Halving height makes it 26\pi

So, halving diameter does not have same effect as halving height.

5 0
3 years ago
What are the solutions to m^2 – 9 = 0? a. m = –9 and m = 0 b. m = –3 and m = 3 c. m = –3 d. m = 9
marysya [2.9K]
2 ways
zero product property
easy way

zero product
factor perfect square
m^2-3^2=0
(m-3)(m+3)=0
set each to zero
m-3=0
x=3

m+3=0
m=-3

m=-3 or 3

easy way
add 9 to both sides
m^2=9
sqrt both sides remember to take postive and negative roots
m=+/-3
m=-3 or 3


B is answer

5 0
3 years ago
Which statement best explains whether △PQR is congruent to △XYZ?
slamgirl [31]
D. because PQR and XYZ are not congruent
5 0
3 years ago
Please help! It’s Saturday and I only have this question left on my digital worksheet!
Natalija [7]

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

<h3>\frac{ {6}^{ - 3} }{ {6}^{5} }</h3>

Using the rules of indices

Since the bases are the same and are dividing we subtract the exponents

That's

<h3>\frac{ {a}^{x} }{ {a}^{y} }  =  {a}^{x - y}</h3>

So we have

<h3>\frac{ {6}^{ - 3} }{ {6}^{5} }  =  {6}^{ -  3 - 5}  =  {6}^{ - 8}</h3>

Using the rules of indices

<h3>{x}^{ - y}  =  \frac{1}{ {x}^{y} }</h3>

So we have the final answer as

<h2>\frac{1}{ {6}^{8} }</h2>

Hope this helps you

4 0
3 years ago
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