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3 years ago

(2 - 5m) (-5) dhwfhsdjduhrhdb ewdewg

Mathematics

1 answer:

Semmy [17]3 years ago

5 0

Answer:

25m−10 would be the answer

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PLEASE HELP!!!!!! (20 POINTS)

Lostsunrise [7]

Answer:

Step-by-step explanation:

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3 years ago

Simplify expression- 9a-4(2a+5)

likoan [24]

Apply the distributive property.
9
a
−
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(
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a
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−
4
⋅
5
9
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8
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−
8
a
−
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a-20

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3 years ago

Ssce 2002 Question 2-core maths

vova2212 [387]

Answer:

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8 0

4 years ago

Read 2 more answers

How is Pythagorean theorem and geometric mean related?

Olegator [25]

Answer:

The two triangles formed are also similar to each other. The measure of the altitude drawn from the vertex of the right angle to the hypotenuse is the geometric mean between the measures of the two segments of the hypotenuse.

Step-by-step explanation:

4 0

3 years ago

You're a contestant on a TV gameshow where you must choose between four identical looking suitcases containing $100, $100, $300,

MA_775_DIABLO [31]

Answer:

0.2990 = 29.90%.

Step-by-step explanation:

For each trial, there are only two possible outcomes. Either you win $400, or you do not. Trials are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of winning $400 in a trial:

1/4 probability of choosing the suitcase containing $400, and in this case, 0.7 probability of keeping it.

3/4 probability of choosing another suitcase. Then, 0.3 of 3/4 probability of changing the suitcase, and 0.5 of 0.3 of 3/4 probability of getting the suitcase containing $400. So

$p = \frac{1}{4}*0.7 + \frac{3}{4}*0.3*0.5 = 0.25*0.7 + 0.75*0.15 = 0.2875$

If you play this game five times, the probability that the event W400 occurs twice in five trials is:_______

This is P(X = 2) when n = 5. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{5,2}.(0.2875)^{2}.(0.7125)^{3} = 0.2990$

The probability is 0.2990 = 29.90%.

8 0

3 years ago