I think the answer is y=10
The minimum value of a function is the place where the graph has a vertex at its lowest point.
There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.
(1) By plotting graph
We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.
(2) By solving equation
The second way to find the minimum value comes when we have the equation y = ax² + bx + c.
If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.
If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
After determining that we actually will have a minimum point, use the equation to find it.
Answer:
your answer to (i) is 5 because anything with a denominator of 0 is undefined
Step-by-step explanation:
Answer: 1. I forgot how you write it but it adds 1/3 of the number, so for example 9/3 is 3, so you add 3 to 9 = 12 and then 21/3 is 7 and so you add 7 to 21 = 28. I forgot how you would write this but I know the answer is not 1/3 though because then that would be dilating. (srry this one isn't clear)
Also sorry I couldn't really help more I'm not very good at this stuff.
For lines to be parallel they must have the same slope. If:
y=mx+b
For any line to be parallel to the above it must also have the same value for m in that line.
