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3 years ago

I need help solving this

Mathematics

2 answers:

Nadya [2.5K]3 years ago

8 0

Answer:

$232 ~cm^2$

Step-by-step explanation:

$2(8*10)+2(2*10)+2(8*2)=$

$2*80+2*20+2*16=$

$160+40+32=$

$232$

hope it helps...

have a great day!!

Tamiku [17]3 years ago

4 0

Answer:

the correct answer is 302cm²

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Find two consecutive whole numbers such that 4/7 of the larger exceeds 1/2 of the smaller by 5

Darina [25.2K]

Answer:

The consecutive numbers are 62 and 63

Step-by-step explanation:

Let the larger number be represented by x and the smaller number by y,

Provided they are consecutive numbers;

$x = y + 1$ --- Equation 1

From the question; we have that

$\frac{4x}{7} = \frac{y}{2} + 5$ --- Equation 2

Required

Find x and y

Multiply both sides of equation 2 by 14

$14 * \frac{4x}{7} = 14 * \frac{y}{2} + 14 * 5$

$2 * 4x = 7 * y + 70$

$8x = 7y + 70$ ---- Equation 3

Substitute y + 1 for x in equation 2

$8(y + 1) = 7y + 70$

Open bracket

$8y + 8 = 7y + 70$

Collect like terms

$8y - 7y = 70 - 8$

$y = 62$

$x = y + 1$

So,

$x = 62 + 1$

$x = 63$

Hence, the consecutive numbers are 62 and 63

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3 years ago

A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin

pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph. Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, $\text{ distance } =\text{ speed }\times \text{ time }$

$\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}$

We are given that, time taken for both are same. So $\frac{40}{a-11}=\frac{70}{a+11}$

$\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}$