Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
Answer:
g = -2
Step-by-step explanation:
6=g+8
Subtract 8 from each side
6-8=g+8-8
-2 =g
If you sketch the path of the boat, you will form a right triangle towards the port. The distance from the port to the present position is the hypotenuse since it is opposite from the right angle formed by the 12 miles north and 5 miles east movement. Since it is a right triangle, use the Pythagorean Theorem to solve the hypotenuse.
Solution:
h² = o² + a²
h² = 12² + 5²
h² = 144 + 25
h² = 169
√h² = √169
h= 13
The present distance of the boat from the port is 13 miles.
Answer:
1. 2x + 5y = 5
2. 3x + 2y = -9
Step-by-step explanation:
