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Serga [27]
2 years ago
14

Combine like terms in the expression 4k + 2k - k + 3. please help this is urgent

Mathematics
2 answers:
victus00 [196]2 years ago
3 0

4k + 2k - k + 3

6k - 1k + 3

5k + 3

Answer: 5k + 3

Leviafan [203]2 years ago
3 0

Answer:

Well

4k + 2k - k +3

Well the like terms here are K.

Just add or subtract the like terms (k) following order of operations.

4k + 2k - k = 5k

3 can’t be combined here.

5k + 3

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6.The perimeter of a rectangle whose length is 7.5cm and breadth 3.75cm​
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Answer:

formulla of perimeter of rectangle

Step-by-step explanation:

perimeter of rectangle=2(l+b)

= 2(7.5+3.25)

=2(11.25)= 22.5

5 0
3 years ago
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Determine the domain of the function (fog) (x) where f(x) = 3x-1/x-4 and g(x)=x+1/x
Mrac [35]

Answer:

(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)

Step-by-step explanation:

The given functions are f(x)=\frac{3x-1}{x-4} and g(x)=\frac{x+1}{x} .

We now composed the two functions to find:

(f\circ g)(x)=f(g(x))

\implies (f\circ g)(x)=f(\frac{x+1}{x})

\implies (f\circ g)(x)=\frac{3(\frac{x+1}{x})+1}{\frac{x+1}{x}-4}

\implies (f\circ g)(x)=\frac{4x+3}{1-3x}

This function is defined if the denominator is not zero.

1-3x\ne0

x\ne\frac{1}{3}

We write this in interval notation as:

(-\infty,\frac{1}{3})\cup (\frac{1}{3},\infty)

We need to be cautious here as x=0 is not in the domain of g(x).

Therefore the domain of (f\circ g)(x) is

(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)

4 0
3 years ago
Can 1 be expressed as a fraction
elixir [45]

  • <em><u>Any integer can be written as a fraction! Just put that integer as the numerator of a fraction with a denominator of 1.</u></em>

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6 0
2 years ago
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How do I "undo" multiplication
Law Incorporation [45]
A way of undoing any operation, is using the inverse of the operation. So if you want to ‘undo’ addition you subtract, and if you want to ‘undo’ multiplication you divide.

Hope this helps!!
8 0
3 years ago
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Help!!! Need Anwser!!!​
jolli1 [7]

Hello.

The answer is choice A. angle 1 = 118, angle 2 = 118

Explanation:

The four angles above are congruent (meaning the same) to the ones beneath.

Angles 1 and 2 are also congruent, so they will measure the same.

Lets label the angles above A, B, C, D.    B being the known angle, which is 118°. The angles beneath can be labelled E, F, G, H.

∠B ≅ ∠D

∠ABCD ≅ ∠EFGH

∠BD ≅ ∠FH

FH (or 1 and 2) equal 118.

4 0
3 years ago
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