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Butoxors [25]
2 years ago
8

20 points

Mathematics
1 answer:
CaHeK987 [17]2 years ago
7 0

Answer:

!!!

Step-by-step explanation:

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A washing machine is filling up with water at a constant rate. The rate is Three-fourths of a gallon in StartFraction 1 over 5 E
konstantin123 [22]

Answer:

3/4 in 1/5 of 60 sec

1/5*60=12

3/4 in 12 seconds

3/4*5=15/4=3 3/4

He multiplied 3/4 by 1/5 instead of by its reciprocal , 5.

12/4=3

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2 years ago
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1. Find the volume of the pyramid.<br> 5 in<br> 11 in<br> 9 in<br> 74
Oduvanchick [21]

The volume of the pyramid with the given length, width and height is 165in³.

<h3>What is the volume of the pyramid?</h3>

The volume of a right rectangular pyramid is expressed as;

V = ( L × W × H ) / 3

Given that;

  • Length L = 11in
  • Width W = 9in
  • Height H = 5in

We substitute into the equation above.

V = ( L × W × H ) / 3

V = ( 11in × 9in × 5in ) / 3

V = 495in³ / 3

V = 165in³

The volume of the pyramid with the given length, width and height is 165in³.

Learn more about volume of pyramid here: brainly.com/question/17615619

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5 0
2 years ago
List the next 3 terms in the following sequence 1,2,4,8,16,32​
SashulF [63]
They are 64, 128, and 256 i do believe
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3 years ago
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I’ll gift u a milf if you answer
Sveta_85 [38]

Answer:

x = - \frac{11}{2}

divide each term by two and simplify.

Give me my milf.

8 0
3 years ago
Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b
jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that  R should represent the set of all possible outcomes generated from  a bit string of length 10 .

So; as each place is fitted with either 0 or 1

\mathbf{|R|= 2^{10}}

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if  a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

\mathbf{P(E) = \dfrac{|E|}{|R|}}

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

\mathbf{{|E|}=1 }   ; \mathbf{|R|= 2^{10}}

\mathbf{P(E) = \dfrac{1}{2^{10}}}

4 0
3 years ago
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