Answer:
A. The fern transitioned from gametophyte generation to sporophyte generation.
Explanation:
Ferns undergo an ALTERNATION of GENERATIONS in their reproductive life cycle. That is, they alternate between an incospicuous gametophytic stage and a dominant sporophytic stage. The sporophyte produces haploid spores, which germinates into the gametophyte plant called PROTHALLUS.
The gametophyte produces gametes (male and female) which fuse together to form the diploid zygote, which eventually develops into the SPOROPHYTE plant via mitosis. In this question, the brown dots from the underside of a fern's leaves that Maria collected are the spores.
When she places them in a pot, the spores germinated into gametophyte stage, then formed sporophyte, which is the small leaves she noticed growing from the pot. From this, it can be observed that the fern is transitioning from GAMETOPHYTE generation to SPOROPHYTE generation.
Answer:
chemical bonds between atoms in reactants
Clostridium, Bacteroides, and the methane-producing archaea (methanogens), are called obligate anaerobes because their energy-generating metabolic processes are not coupled with the consumption of oxygen.
Answer:
3/16
Explanation:
Given,
Black coat color is dominant over brown coat color.
Long mane is dominant over short mane.
BBLL X bbll =
F1: BbLl = Entire progeny has black color and long mane
BbLl progeny will produce BL, Bl, bL and bl gametes. When they interbreed, the resultant F2 progeny will be in 9:3:3:1 dihybrid ratio. Hence in F2,
BBLL : BbLL : bbLl : bbll = 9 : 3 : 3 : 1
3/16 progeny will have bbLl genotype hence 3/16 progeny will have brown, long mane.
