You can create two equations.
"<span>A car travels 20 mph slower in a bad rain storm than in sunny weather."
</span>
![\sf x-20=y](https://tex.z-dn.net/?f=%5Csf%20x-20%3Dy)
Where 'x' represents speed in sunny weather and 'y' represents speed in rainy weather.
"<span>The car travels the same distance in 2 hrs in sunny weather as it does in 3 hrs in rainy weather."
![\sf 2x=3y](https://tex.z-dn.net/?f=%5Csf%202x%3D3y)
</span>Where 'x' represents speed in sunny weather and 'y' represents speed in rainy weather.
We want to find the speed of the car in sunny weather, or 'x'. Plug in the value for 'y' in the first equation into the second equation.
![\sf \boxed{\sf x-20}=y](https://tex.z-dn.net/?f=%5Csf%20%5Cboxed%7B%5Csf%20x-20%7D%3Dy)
![\sf 2x=3y\rightarrow2x=3(x-20)](https://tex.z-dn.net/?f=%5Csf%202x%3D3y%5Crightarrow2x%3D3%28x-20%29)
Distribute:
![\sf 2x=3x-60](https://tex.z-dn.net/?f=%5Csf%202x%3D3x-60)
Subtract 3x to both sides:
![\sf -x=-60](https://tex.z-dn.net/?f=%5Csf%20-x%3D-60)
Divide -1 to both sides:
![\sf x=60](https://tex.z-dn.net/?f=%5Csf%20x%3D60)
So the car goes 60 mph in sunny weather.
(2x 6)(x-1)=0 happy to help :)
Answer:
10%
Step-by-step explanation:
Percentage increase for any change is calculated by formula
{(Final value - initial value)/initial value} * 100
Given
population in 2010 = 2 million ----------->initial value
population in 2015 = 2.2 million ----------->Final value
![Percentage \ \ increase = {(2.2 - 2)/2} *100= (0.2/2)*100 = 10%](https://tex.z-dn.net/?f=Percentage%20%20%5C%20%20%5C%20increase%20%3D%20%7B%282.2%20-%202%29%2F2%7D%20%2A100%3D%20%280.2%2F2%29%2A100%20%3D%2010%25)
Answer:
12
Step-by-step explanation:
Since this is simple interest the equation will be P*T*R=I T=time which is 1 year. P=money invested or borrowed (aka princable) which is 400$. R=Annual rate is 3% per year and I= Interest after the number of years (aka answer) Hope this helps :)
Answer:A≈153.94in²
Step-by-step explanation:Hope this was helpful