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2 years ago

15

69+69+69+69+69+69+6?

2 answers:

ss7ja [257]2 years ago

6 0

Answer:

420

Step-by-step explanation:

Simple addition! I double checked!

atroni [7]2 years ago

6 0

Answer:

69

Step-by-step explanation:

696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969696969

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Five friends want to rent a go-cart track that costs $100. Each friend intends to contribute the same about. Susan used the five

elena-s [515]

5 friends contribute x money to go to a cart that costs $100.
.
5x = 100
x = 100/5
x = 20
.
Each friend contributed $20 for the cart

8 0

2 years ago

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Bas_tet [7]

Answer:

Lindsey jogged 3/4 of a mile in 1/6 hour how far did she jog in 1 hour?

3 over 4 divided by 1 over 6 is equal to 3 over 4 times 6 over 1 4 and half when simplified

She ran 4.5 miles in 1 hour.

Step-by-step explanation:lol

5 0

2 years ago

Pls answer as soon as possible thanks :)

denis23 [38]

Answer:

Step-by-step explanation:

0.22 ,2.22%, 2.22 ,2.222

2/9 turns into 0.22 and it is the least than you have the percentage and so on

7 0

2 years ago

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X²+y²-6x+14y-1=0<br> and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0

2 years ago

Solve E = mc2 for c. A) c = E m B) c = m E C) c = + m E D) c = + E m

S_A_V [24]

$C=\sqrt{E/M}$

enjoy the rest of your day!

6 0

3 years ago

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