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zysi [14]
4 years ago
6

How do you solve these problems?

Mathematics
1 answer:
Rzqust [24]4 years ago
6 0
A)

\bf log_4(x)=3\\\\
-----------------------------\\\\
log_{{  a}}{{  a}}^x\implies x\qquad \qquad 
\boxed{{{  a}}^{log_{{  a}}x}=x}\impliedby 
\begin{array}{llll}
\textit{we'll use this}\\
\textit{cancellation rule}
\end{array}\\\\
-----------------------------\\\\
4^{\cfrac{}{}log_4(x)}=4^3\implies x=4^3

b)

\bf 3^{2y}=81\qquad 
\begin{cases}
81=3\cdot 3\cdot 3\cdot 3\\
\qquad 3^4
\end{cases}\implies 3^{2y}=3^4\impliedby 
\begin{array}{llll}
\textit{same base}\\
exponents\\
must\ be\\
the\ same
\end{array}
\\\\\\
2y=4\implies y=\cfrac{4}{2}\implies y=2
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Option (1)

Step-by-step explanation:

Fastest time recorded = 50 yards dash is 5.2 seconds.

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\frac{50\text{yd}}{5.2\text{sec}}\times \frac{3\text{ft}}{1\text{yd}}\times \frac{1\text{ mile}}{5280\text{ft}}\times \frac{60\text{sec}}{1\text{min}}\times \frac{60\text{min}}{1\text{hr}}

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4 years ago
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PLEASE HELP<br> What is the formula to find a square pyramid?
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3 years ago
Si un triángulo tiene una hipotenusa de 15 cm y un cateto que mide 12 cm, ¿cual es la longitud del otro cateto?
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9cm

Explicación:

El teorema de pitagoras nos dice que la hipotenusa al cuadrado es igual a la suma de los catetos al cuadrado:

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Donde c es la hipotenusa y a  y b son los catetos.

Por lo cual, podemos reemplazar c por 15cm y a por 12cm :

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Por lo tanto, la longitud del otro cateto es 9 cm

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3 years ago
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