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alina1380 [7]
2 years ago
10

Find the zero of the function.

Mathematics
1 answer:
Shalnov [3]2 years ago
8 0
The answers is x =3 , x= -10
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Which property is illustrated?<br><br> 15 + (5 + 7) = (15 + 5) + 7
Ainat [17]

Associative Property !!


hope this helped!!!                                                

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2 years ago
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Aleks04 [339]

Answer:

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the length of a rectangle is 5cm greater than the width. the area of the rectangle is 84cm squared. find the length and width
Ymorist [56]

Answer:

Therefore,

Length=12\ cm

Width= 7\ cm

Step-by-step explanation:

Let the Width of rectangle be 'x' cm.

Then the length of a rectangle will be (x + 5) cm.

Area of rectangle given is 84 cm squared.

To Find:

Length = (x+5) = ?

Width = x = ?

Solution:

We have area of rectangle given as

\textrm{Area of Rectangle}=Length\times Width

Substituting the given values we get

84=(x+5)x\\x^{2} +5x-84=0\\

On factorizing we get

x^{2} +12x-7x-84=0\\x(x+12)-7(x+12)=0\\(x+12)(x-7)=0\\(x+12)=0\ or\ (x-7)=0\\x=-12\ or\ x=7\\\therefore x =7\ cm\ \textrm{As x cannot be negative}

Therefore,

Length=x+5=7+5=12\ cm

Therefore,

Length=12\ cm

Width= 7\ cm

8 0
3 years ago
What is the algebraic expression for the quotient of a number and nine
maxonik [38]
The algebraic expressions would be a÷9
3 0
3 years ago
Substitution method<br>6x-7y=5,3x+y=-1​
uranmaximum [27]

Answer:

x =  -  \frac{2}{27}

y =  -  \frac{4}{5}

Step-by-step explanation:

Lets call

6x - 7y = 5

equation 1

3x + y =  - 1

equation 2

using equation 2, we would make y the subject of the formula as it would be easier

y =  - 1 - 3x

This would now be called our equation 3

Now the next step is to substitute equation 3 in equation 1

6x - (7( - 1 - 3x)) = 5

6x - ( - 7 - 21x) = 5

6x + 7 + 21x = 5

27x = 5 - 7

27x =  - 2

Divide both sides by 27\frac{27x}{27}  =   -  \frac{2}{27}

x =  \frac{ - 2}{27}

Substitute the value of x in equation 2

3( \frac{ - 2}{27} ) + y =  - 1

-  \frac{ 2}{9}  + y =  - 1

y =  - 1 +  \frac{2}{9}

y =  -  \frac{ 8}{10}

y =   -  \frac{4}{5}

6 0
2 years ago
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